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amm1812
3 years ago
10

Yoo i need help !!! its math and i havent learned it yet

Mathematics
2 answers:
Kitty [74]3 years ago
6 0

Answer:

9x+18

Step-by-step explanation:

Let y=x/9 -2

or,9y+18=x

or,f(x)=9y+18

Then,f^-1(x)=9x+18

BlackZzzverrR [31]3 years ago
4 0

Answer:

{f}^{ - 1} (x) = 9x + 18

Step-by-step explanation:

f(x) =  \frac{1}{9}x - 2

y = \frac{1}{9} x - 2

x =  \frac{1}{9}y - 2

x + 2 =  \frac{1}{9}y

9x + 18 = y

{f}^{ - 1} (x) = 9x + 18

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Jamie is walking her neighbors’ dog while they are away. She is keeping track of the total number of blocks she walks over time.
jok3333 [9.3K]
C yes because the ratios are equivalent between each pair of values
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Suppose you invest $10,410 in equipment to manufacture a new board game. Each game costs $2.65 to manufacture and sells for $20.
leva [86]
Let x= number of board games 
<span>20x=10410+2.65x </span>
<span>-2.65 -2.65 </span>
<span>17.35x=10410 </span>
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3 years ago
El costo de producir 10 juegos de video al día es de 350 dólares , mientras que producir 30 juegos del mismo tipo al día cuestan
Dovator [93]

Answer:

El coste de producir un juego de vídeo es de 125 dólares.

Step-by-step explanation:

(This exercise is written in Spanish and is incomplete. Complete statement will be presented below)

El costo de producir 10 juegos de video al día es de 350 dólares , mientras que producir 30 juegos del mismo tipo al día cuestan 850 dólares . Si suponemos un modelo lineal como el descrito anteriormente , determine:

¿Cuál es el costo de producir un juego de vídeo?

(Explanation will be held in Spanish)

El modelo lineal es un polinomio de primer orden de la forma:

y = a\cdot x + b

Donde:

x - Variable independiente (eje x - Cantidad de juegos de vídeo producidos - Adimensional)

y - Variable dependiente (eje y - Coste de producción de juegos de vídeo - Dólares)

a - Pendiente de la función.

b - Intercepto en el eje y.

Dados los dos costes para dos cuotas distintas de producción, se construye el siguiente sistema de ecuaciones lineales:

10\cdot a + b = 350

30 \cdot a + b = 850

Se resuelve el sistema con algo de manipulación algebraica:

(30\cdot a + b) - (10\cdot a + b) = 850 - 350

20 \cdot a = 500

a = 25

Luego:

b = 850 - 30\cdot a

b = 100

La ecuación lineal es:

y = 25\cdot x +100

Finalmente, el coste de producir un juego de vídeo es:

y = 25 \cdot (1) + 100

y = 125

El coste de producir un juego de vídeo es de 125 dólares.

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Pentagon with a side of 6 ft
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A) S, Q, and B

Hope that help you!

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