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forsale [732]
3 years ago
10

CAN SOMEONE HELP ME WITH #1????

Mathematics
1 answer:
lina2011 [118]3 years ago
5 0
5/6, .23, -5 3/8, .324....
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It's not multiple choice, anyone know the answer I'm stuck :(
lana66690 [7]

Answer:

regular polygon of 9 sides has 9 lines of symmetry

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HELP ME WITH THESE TWO PLS !! I'LL GIVE BRAINLIEST
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that is a two sided triangle

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In the New York State daily lottery game, a sequence of 4 (not necessarily different) digits in the range of 0-9 is selected at
devlian [24]

Answer:

50.40% probability that all 4 are different.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

4 digits, all different

For the first digit, it can be any of them, so there are 10 possible

For the second digit, it can be any of them other than the first digit. So there are 9 possible.

For the third digit, it can be any of them, other than the first and the second. So there are 8 possible.

By the same logic, 7 possible digits for the fourth. So

D = 10*9*8*7 = 5040

Total outcomes:

4 digits, each can be any of them(10 from 0 - 9).

So

T = 10*10*10*10 = 10000

Probability:

p = \frac{D}{T} = \frac{5040}{10000} = 0.5040

50.40% probability that all 4 are different.

5 0
3 years ago
What is the slope of the line that passes through (2,5) and (3,6).
earnstyle [38]

Answer:

1

Step-by-step explanation:

hope this help:) I use slop formula

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3 years ago
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Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is
maw [93]

There are 120 ways in which 5  riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

Now,

Substituting values,

We get,

^5N_5 = \frac{5!}{(5-5)!}

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5  riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0
2 years ago
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