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kvasek [131]
3 years ago
15

The product of 40 and the distance to the finish line

Mathematics
1 answer:
nalin [4]3 years ago
5 0

Answer:

there is no picture

Step-by-step explanation:

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Problem page the ratio of men to women working for a company is 5 to 8 . if there are 169 employees total, how many women work f
Ksenya-84 [330]
5 : 8....added = 13

5/13(169) = 845/13 = 65 men
8/13(169) = 1352/13 = 104 women <===
8 0
3 years ago
Calculate the rate of change of the linear function that contains the points
Mandarinka [93]

Answer:

-2

Step-by-step explanation:

X1 Y1 X2 Y2

(-15, 30) (7, -14)

Y2-Y1 = -14-30 = -44 = -2

———————————————

X2-X1 = 7-(-15)= 22 = 1

3 0
3 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
PLEASE HELP IVE BEEN STUCK FOR HOURS!
kirza4 [7]
13
14=2•7
15=3•5
16=2•2•2•2
17
18=2•3•3
19
20=2•2•5
...
5 0
3 years ago
(x - 5)2 = x2 + 25<br> always or sometimes true???
____ [38]

Answer: No real solution

Step-by-step explanation:

6 0
3 years ago
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