Answer:
Step-by-step explanation:
Hi there,
The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.
To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.
With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.
Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!
thanks,
Joel = j, Mark = m, Sandra = s
j + m + s = 120
m = 3j
j = 1/2 s --> s = 2j
plug in (substitute) each letter to make it in terms of only j: j + m + s = 120
j + 3j + 2j = 120
6j = 120
6j/6 = 120/6
j = 20
now plug in for the j & s equation:
s = 2j = 2(20) = 40
Therefore Sandra has 40 coins!
Answer:
z=35.1
Step-by-step explanation:
-- The graph looks like a line that passes through the origin,
and slopes up to the right at a 45-degree angle.
-- Point #1 on the line:
. . . . . Pick any number.
. . . . . Write it down twice.
. . . . . Call the first one 'x'. Call the second one 'y'.
-- Point #2 on the line:
. . . . . Pick any other number.
. . . . . Write it down twice.
. . . . . Call the first one 'x'. Call the second one 'y'.
-- Point #3 on the line:
. . . . . Pick any other number.
. . . . . Write it down twice.
. . . . . Call the first one 'x'. Call the second one 'y'.
Rinse and repeat, as many times as you like,
until the novelty wears off and you lose interest.
F and E are congruent with the figure above
