Hello its meee happy bew year
Given:
Quadrilateral PQRS
P(o, o), Q(a+c, o), R(2a+c, b), S(a, b)
Find:
whether the diagonals are perpendicular using coordinate geometry
Solution:
If the diagonals are perpendicular, their slopes multiply to give -1.
The slope of PR is
(b-o)/(2a+c-o)
The slope of QS is
(b-o)/(a-(a+c)) = (b-o)/(-c)
The product of these slopes is
(b-o)·(b-o)/((2a+c-o)(-c))
This value will not be -1 except for very specific values of a, b, c, and o.
It cannot be concluded that the diagonals of PQRS are perpendicular based on the given coordinates.
Answer:
111 is X
Step-by-step explanation:
So the theroum for any extended angle is to add the two opposite angles.
So if you add the 2 numbers is suppose to be X.
75+36=111
Thats it
Answer:
13.6
Step-by-step explanation:
Given,
n = 4
To find : 14 - 10/n = ?
Answer : -
14 - 10/4
= 14 - 2/5
= 14 - 0.4
= 13.6
Therefore,
the correct answer is 13.6
It’s A
six more than a number which is y- (y+6)
is 10.03
so y+6=10.03
