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maks197457 [2]
4 years ago
5

When an object moves in uniform circular motion, the direction of its acceleration is A) in the same direction as its velocity v

ector. B) in the opposite direction of its velocity vector C) is directed toward the center of its circular path. D) is directed away from the center of its circular path. E) depends on the speed of the object.
Physics
2 answers:
Effectus [21]4 years ago
5 0

<em><u>Hello There!</u></em>

<em><u></u></em>

<em><u>When an object moves in uniform circular motion, the direction of its acceleration is directed toward the center of its circular path.</u></em>

<em><u></u></em>

Uniform circular motion is a certain object or thing that that is traveling in a circular path. The reason why "uniform" is there because a part of it has to stay constant.

Sonja [21]4 years ago
3 0

Answer:

C) is directed toward the center of its circular path.

Explanation:

Uniform Circular Motion happens when its trajectory is a circumference and its velocity modulus remains constant over time.

In our daily life we often observe the movement made by fans, car wheels and also by the blender. These are all examples of devices that use MCU.

Within the study of uniform circular motion there is the presence of centripetal acceleration, ie when there is speed variation there is acceleration.

Centripetal acceleration is always directed to the center of the circumference. It does not change the modulus of velocity and its mathematical representation is given by the equation:

                                 acp = v2 / R or acp = ω2 R

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The c-cl bond dissociation energy in cf3cl is 339 kj/mol. What is the maximum wavelength of photons that can rupture this bond?
ruslelena [56]

Answer:

3.53*10^{-7} m

Explanation:

Photon that can rupture the bonds are those with the energy of the bond dissociation energy. If we want to know the energy for each molecule we have to take into account that:

1mol=6.022*10^{23}molecule

Hence, we have

E_d=339\frac{10^{3}J}{mol}*\frac{1mol}{6-022*10^{23}molecules}=5.62*10^{-19}J/molecule

but the energy is also:

E_d=h\nu =\frac{hc}{\lambda}\\\\\lambda=\frac{hc}{E_d}

where h is the Planck's constant and c is the speed of ligth. By replacing we obtain:

\lambda=\frac{(6.62*10^{-34}Js)(3*10^{8}m/s)}{5.62*10^{-19}J}=3.53*10^{-7}m

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Newton's law of cooling states that the rate of change of temperature of an object in a surrounding medium is proportional to th
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3 years ago
A grinding wheel is a uniform cylinder with a radius of 8.5cm and a mass of 0.580kg. Calculate
Kaylis [27]

Answer:

(a) its moment of inertia about its center is 0.002095 kgm²

(b) Applied torque is 0.071813 Nm

Explanation:

Given;

Radius of the grinding wheel, R = 8.5cm

Mass of the grinding wheel, m = 0.580kg

Part (a) its moment of inertia about its center

I = ¹/₂MR²

I = ¹/₂(0.58)(0.085)²

I = 0.002095 kgm²

Part (b)

Given;

initial angular velocity, ωi = 1500rpm = 157.1 rad/s

final angular velocity, ωf = 1500rpm = 157.1 rad/s

Initial torque, τi = I x αi

αi = ωi / t

αi = 157.1 / 5 = 31.42 rad/s²

τi = 0.002095 x 31.42

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Final torque, τf =  I x αf

αf = ωf / t

αf = 157.1 / 55 = 2.856 rad/s²

τf = 0.002095 x 2.856

τf = 0.005983 Nm

Applied torque = τi + τf

                          =  0.06583 Nm + 0.005983 Nm

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There is an applied force by your hand on the ball when you hit the ball down. The ball also applies the same force on your hand in the opposite direction.
4 0
3 years ago
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