You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
If x=6 and y=5 and we are to find y when x=3.
it will be 6=5,3=y....
5×3=6×y.
y=15/6=2.5 or 2 whole number 1/2.
This is the answer I hope it helps
B is true; pi= ~3.14. 3+4 is equal to 7, so because pi is greater than 3, pi+4>7
Answer:
For the first blank: 8
For the second blank: I think it's 913
Step-by-step explanation:
First blank: To find the area of a square do (Length * Width) For the roof do 15 * 25 to get 375. Then divide by 100 and you get 3.75 but round to 4
That's for 1 half of the roof so do cover the whole roof you need 8.
The answer to the first one is a
