The answer is no, the static charge would still be there.
Answer:
220.7
Explanation:
distance traveled is 1.5*5=7.5m
PE gain is MGH=3*9.81*7.5=220.7
Answer:
(from top to bottom)
350 N, 80 kg, 10 m/s^2, 80 kg, -15 m/s^2, -3000 N
Explanation:
Force = Mass*Acceleration (aka F = ma)
Using algebra, you can find the variables/unknown values.
a = acceleration of the bank cart = 4 m/s²
m = mass of the bank cart = 8000 kg
F = net force on the cart
According to newton's second law , Net force is the product of mass of the object and the acceleration of the object.
Net force = mass x net acceleration
hence Net force acting on the cart is given as
F = ma
F = 8000 x 4
F = 32000 N
hence the net force acting on the cart comes out to be 32000 N
Answer:
τ = 32.8635 N-m (counterclockwise)
Explanation:
Given
M = 2 kg
L = 2 m
r = 0.10 m
m₁ = 4 kg
r₁ = (1.00-0.30)m = 0.70 m
m₂ = 5 Kg
r₂ = (0.90-0.75)m = 0.15 m
In order to determine the torque on the meterstick if it is received and allowed to pivot about the 90 cm mark (ypu can see the pic to understand the question), we apply:
τ = r₁*m₁*g + r₂*m₂*g - r*M*g = g*(r₁*m₁+r₂*m₂-r*M)
⇒ τ = (9.81 m/s²)(0.70 m*4 kg + 0.15 m*5 Kg - 0.10 m*2 kg)
⇒ τ = 32.8635 N-m (counterclockwise)