We use the equation of motion for vertical component,

Here,
is displacement of bullet,
is vertical initial velocity of bullet which is equal to zero because bullet was fired horizontally, and t is time of flight.
Therefore,

Given, 
Substituting the values, we get time of flight

Answer:
= 5.1 W
Explanation:
time (t) = 30 ms = 0.03 s
mass (m) = 560 g = 0.56 kg
initial velocity (U) = 0 m/s
final velocity (V) = 0.74 m/s
power = \frac{work done}{t} = \frac{f x d}{t} = f x v = m x a x v
m x a x v = m x \frac{V-U}{t} x \frac{V + U}{2}
m x \frac{V-U}{t} x \frac{V + U}{2} = 0.56 x \frac{0.74 - 0}{0.03} x \frac{0.74+0}{2}
= 5.1 W
Answer:

Explanation:
given,
P (in kilo pascals), volume V (in liters), temperature T (in kelvins)
P V = 8.31 T
Rate of increase the temperature = 0.1 K/s
temperature = 285 K
Pressure = 18 kPa
increasing at the rate of 0.07 k Pa/s
Rate at which volume is changing = ?





Answer:
Speed of faster train equals 29 mph
Explanation:
Let the speed of slower train be 'x' miles per hour and the speed of faster train be 'y' miles per hour.
Distance that slower train covers in 2 hours=
Distance that faster train covers in 2 hours=
Since they move at right angles the distance between them can be found by Pythagoras formula as

It is given that 
Using this in the above equation we get

This is a quadratic equation in 'x'
Comparing with standard quadratic equation
we get value of x as

Thus speed of faster train = 28.58 mph
Speed of faster train = 19 mph