Answer:
Port scan targeting 192.168.1.106.
Explanation:
In the following question, there is some part of the question and options is missing.
In the following statement, when a file log is taken from the computer system which has Internet Protocol address is given in the statement and by the further details of the statement in which time and the port destination by examine those details of the Internet Protocol, the following port scan targeting the IP address 192.168.1.106.
Answer:
The program to this question can be given as follows:
Program:
public class data //defining class data
{
//main method
public static void main (String [] as) //declaring main method
{
int userNum = 4; //declare variable userNum and assign value
for (userNum = 1; userNum <= 4; userNum++) //loop for print values
{
System.out.println(userNum); //print values in new lines.
}
}
}
Output:
1
2
3
4
Explanation:
In the above java program code firstly a class "data" is defined, inside this class the main method is defined in which an integer variable userNum is defined that holds a value that is "4".
- In this method, a for loop is declare that uses variable userNum which starts from 1 and ends with a given value that is equal to 4.
- Inside a for loop, the print function is used that print userNum variable each values in the newline.
Answer: The code below can display directory as stated in the question
Explanation:
char *
gnu_getcwd ()
{
size_t size = 100;
while (1)
{
char *buffer = (char *) xmalloc (size);
if (getcwd (buffer, size) == buffer)
return buffer;
free (buffer);
if (errno != ERANGE)
return 0;
size *= 2;
}
}
Explanation:
The first 3 lines of code tell the user to input a 5 digit number (ex. 72,910) or a 1 digit number (ex. 3). The next 5 lines of code determine if it is a 5/1 digit number or not. If it is, it prints "Success!". The rest of the code just tells that if it's not a 5/1 digit number, and if it's not, it gives errors and tells the user to try again.
Hope this helps!
