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Arte-miy333 [17]
2 years ago
13

Cassie has 8 red marbles and 12 yellow marbles. Her mom doubles her red and yellow marbles. Use the distributive property to sho

w how many marbles Cassie has.
Mathematics
2 answers:
Burka [1]2 years ago
6 0
(8+12) x 2 = 40
You add the yellow and the red marbles then multiply that answer by two
Karo-lina-s [1.5K]2 years ago
5 0

Answer:

Cassie has 40 marbles, 16 red marbles and 24 yellow marbles

Step-by-step explanation:

If Cassie has 8 red marbles and 12 yellow marbles and they are doubled. We can calculate the total amount of marbles cassie has.

[tex]=2\cdot{8}+2\cdot{12}=16+24=40{/tex]

Cassie has 40 marbles, 16 red marbles and 24 yellow marbles

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denis23 [38]

Answer:

y=1/2-2

Step-by-step explanation:

3 0
2 years ago
Find the mode of the following set of data:<br> 5, 8, 2, 5, 2,5<br> A 5<br> B) 2<br> C 2 and 5
Mandarinka [93]

Answer:

A  5   is the mode of the data

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2 years ago
Read 2 more answers
We roll a fair die repeatedly until we see the number four appear and then we stop. The outcome of the experiment is the number
muminat

Answer:

0

Step-by-step explanation:

given that we roll a fair die repeatedly until we see the number four appear and then we stop.

the number 4 can appear either in I throw, or II throw or .... indefinitely

So X = the no of throws can be from 1 to infinity

This is a discrete distribution countable.

Sample space= {1,2,.....}

b) Prob ( 4 never appears) = Prob (any other number appears in all throws)

= \frac{5}{6} *\frac{5}{6} *\frac{5}{6} *\frac{5}{6} *...\\=(\frac{5}{6} )^n

where n is the number of throws

As n tends to infinity, this becomes 0 because 5/6 is less than 1.

Hence this probability is approximately 0

Or definitely 4 will appear atleast once.

8 0
3 years ago
Jordan’s class has 30 boys. If the students in his class, 60% are girls. How many girls are in Jonathan’s class?
aev [14]

There are 45 girls in Jonathan's class.

4 0
3 years ago
a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel
adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

                             = 24000 - 750x + 2400x - 75x²

                             = 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

                                    = $ 150 + 165

                                    = $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0
2 years ago
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