Answer:
4(3n+2) or 12n+8
Step-by-step explanation:
Given expression is:

The numerator of the fraction will be multiplied with 9n^2- 4
So, Multiplication will give us:

We can simplify the expression before multiplication.
The numerator will be broken down using the formula:
![a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}](https://tex.z-dn.net/?f=a%5E2%20-%20b%5E2%20%3D%20%28a%2Bb%29%28a-b%29%5C%5CSo%2C%5C%5C%3D%20%5Cfrac%7B8%5B%283n%29%5E2%20-%20%282%29%5E2%5D%7D%7B6n-4%7D%5C%5C%20%3D%20%5Cfrac%7B8%283n-2%29%283n%2B2%29%7D%7B6n-4%7D)
We can take 2 as common factor from denominator

Hence the product is 4(3n+2) or 12n+8 ..
Part A:
6 2/3 *3 1/2 = 4 1/4 * x
Part B:
20/3 * 7/2 = 17/4 *x
x=20/3 * 7/2 * 4/17
x=(20*7*4) / (3*2*17)
x=560 / 102
<span>x= 5 25/51</span>
=(-17) - 4
=(-17) + (-4)
=(-21)
Answer:
<em>
x−y
=
9
, x
+
y
=
6</em>
<em>x
+
y
=
4 , x
−
y
=
2</em>
<em>x
+
2
y
=
4 , x
−
y
=
−
3 </em>
<em>try out these examples?</em>
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