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timurjin [86]
4 years ago
14

Please help. will give brainliest and 100 pts​

Chemistry
2 answers:
Alex777 [14]4 years ago
8 0

Answer:

1.

%K = 31.904%

%Cl = 28.930%

%O = 39.166%

2.

Hg = 80.69/ 200.59 = 0.40/0.2 = 2

S = 6.436/ 32.07 = 0.20/0.2 = 1

O = 12.87/ 16.00 = 0.80/0.2 = 4

Hg2SO4 is the empirical formula

Explanation:

brainliest please?

RoseWind [281]4 years ago
4 0

Answer:

your welcome

Explanation:

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What is the maximum mass of zinc oxide that can be produced by the reaction of 42.900000000000006g of zinc sulfide and 44.187000
Masja [62]

Answer:

Mass = 0.00541 g

Explanation:

We will convert the larger given values in to smaller by rounding these figures.

Given data:

Mass of zinc sulfide = 43 g

Mass of oxygen = 44.2 g

Mass of zinc oxide = ?

Solution:

Chemical equation:

2ZnS + 3O₂ → 2ZnO + 3SO₂

Number of moles of ZnS:

<em>Number of moles = mass/ molar mass </em>

Number of moles =  43 g/ 97.5 g/mol

Number of moles = 0.44 mol

Number of moles of Oxygen:

<em>Number of moles = mass/ molar mass </em>

Number of moles =  44.2 g/ 32 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.

                             ZnS        :       ZnO

                                2          :          2

                              0.44       :         0.44

                              O₂          :          ZnO

                              3           :            2

                              1.4          :           2/3×1.4 =0.93

The number of moles of zinc oxide produced by ZnS are less so it will limiting reactant.

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Mass = number of moles / molar mass

Mass = 0.44 mol / 81.38 g/mol

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3 years ago
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Answer:

Expert Verified

Explanation:

For short duration: ... When excess of carbon dioxide gas is passed through lime water then the white precipitate calcium carbonate formed first dissolves due to the formation of a soluble salt calcium hydrogen carbonate (Ca(HCO3)2, and the Solution becomes clear again

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Answer:

7,38 g of K₃PO₄

Explanation:

Molarity is an unit of chemical concentration. 0,139 M means 0,139 moles of solute per liter of solution.

In this case, the solute is potassium phosphate (K₃PO₄; molar mass: 212,27 g/mol) and the volume of the solution must be 250mL≡0,25L.

Thus, the moles of potassium phosphate you need are:

0,139 mol/L×0,25L = 0,03475 moles of K₃PO₄

In grams:

0,03475 moles of K₃PO₄ × \frac{212,27g}{1mol} = 7,38 g of K₃PO₄

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