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lord [1]
3 years ago
6

For each system listed in first column of the table below, decide (if possible) whether the change described in the second colum

n will increase the entropy For each system listed in first column of the tabl of the system, decrease For each system listed in first column of the tabl , or leave unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column.SystemChange?SA few moles of nitrogen (N2) gas.The nitrogen is compressed from a volume of to a volume of while the temperature is held constant at <?S0=?S0>?S0not enough informationA few grams of liquid acetone ((CH3)2CO).The acetone evaporates at a constant temperature of <?S0=?S0>?S0not enough informationA few moles of nitrogen (N2) gas.The nitrogen is cooled from to and is also expanded from a volume of to a volume of <?S0=?S0>?S0not enough informationFor each system listed in first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy For each system listed in first column of the tabl of the system, decrease For each system listed in first column of the tabl , or leave unchanged. If you don't have enough information to decide, check the "not enough information" button in the last column.SystemChange?SA few moles of nitrogen (N2) gas.The nitrogen is compressed from a volume of to a volume of while the temperature is held constant at <?S0=?S0>?S0not enough informationA few grams of liquid acetone ((CH3)2CO).The acetone evaporates at a constant temperature of <?S0=?S0>?S0not enough informationA few moles of nitrogen (N2) gas.The nitrogen is cooled from to and is also expanded from a volume of to a volume of <?S0=?S0>?S0not enough information
Chemistry
1 answer:
Olin [163]3 years ago
4 0
The answer could be 25
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Which is correct for kinetic particle theory. (It can be all correct or 2 of them correct)
alisha [4.7K]

The answer is that all of them are correct.

7 0
4 years ago
One type of sunburn occurs when skin is exposed
julia-pushkina [17]

Answer:

E = 6.27 × 10⁻²³ Joules

Explanation:

E = h (Plancks constant) × f (frequency)

(Plancks constant = 6.63 × 10⁻³⁴ J×s)

f = λ × c (used to find frequency so you can satisfy energy equation)

*Have to find wavelength in meters to multiply by speed of light*

1. f = (3.15 × 10⁻⁷ m) × (3 × 10⁸ m/s)

2. f = 9.45 × 10¹⁰ s

3. E = (6.63 × 10⁻³⁴ J×s [Plancks constant]) × (9.45 × 10¹⁰ s)

E = 6.27 × 10⁻²³ Joules

8 0
3 years ago
Determine the mass in grams of 5.15 × 10²¹ atoms of chromium. (The mass of one mole of chromium is 52.00 g.)
Dennis_Churaev [7]

The mass of 5.15 × 10²¹ atoms of chromium is 0.44 g

From Avogadro's hypothesis,

6.02×10²³ atoms = 1 mole of Cr

But:

1 mole of Cr = 52 g

Thus, we can say that:

6.02×10²³ atoms = 52 g of Cr

With the above information, we can obtain the mass of 5.15 × 10²¹ atoms of chromium. This can be obtained as follow:

6.02×10²³ atoms = 52 g of Cr

Therefore,

5.15×10²¹ atoms = (5.15×10²¹ × 52) / 6.02×10²³

5.15×10²¹ atoms = 0.44 g of Cr

Thus, the mass of 5.15 × 10²¹ atoms of chromium is 0.44 g

Learn more: brainly.com/question/15488332

5 0
2 years ago
What is the name of this molecule?<br><br> H3C - C ≡ C - CH3<br><br> Answer: 1,2,3, or 4-butyne?
Semenov [28]

Explanation:

The given molecule is

H3C - C ≡ C - CH3

The numbering order is shown below:

H3C - C ≡ C - CH3

    1     2     3     4

So, the alkyne group is in the second position.

The carbon chain has four carbons.

Hence, the IUPAC name of the given compound is:

2-butyne.

8 0
3 years ago
How many grams of oxygen are required to burn 13.5 g of acetylene
Vinil7 [7]

Answer:

41.54 grams of oxygen are required to burn 13.5 g of acetylene

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₂H₂: 2 moles
  • O₂: 5 moles
  • CO₂: 4 moles
  • H₂O: 2 moles

Being the molar mass of the compounds:

  • C₂H₂: 26 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₂H₂: 2 moles* 26 g/mole= 52 grams
  • O₂: 5 moles* 32 g/mole= 160 grams
  • CO₂: 4 moles* 44 g/mole= 176 grams
  • H₂O: 2 moles* 18 g/mole= 36 grams

You can apply the following rule of three: if by stoichiometry 52 grams of acetylene react with 160 grams of oxygen, 13.5 grams of acetylene react with how much mass of oxygen?

mass of oxygen=\frac{13.5 grams of acetylene*160 grams of oxygen}{52 grams of acetylene}

mass of oxygen= 41.54 grams

<u><em>41.54 grams of oxygen are required to burn 13.5 g of acetylene</em></u>

<u><em></em></u>

8 0
3 years ago
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