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Nitella [24]
3 years ago
8

What is the maximum mass of zinc oxide that can be produced by the reaction of 42.900000000000006g of zinc sulfide and 44.187000

000000005g of oxygen?
Chemistry
1 answer:
Masja [62]3 years ago
5 0

Answer:

Mass = 0.00541 g

Explanation:

We will convert the larger given values in to smaller by rounding these figures.

Given data:

Mass of zinc sulfide = 43 g

Mass of oxygen = 44.2 g

Mass of zinc oxide = ?

Solution:

Chemical equation:

2ZnS + 3O₂ → 2ZnO + 3SO₂

Number of moles of ZnS:

<em>Number of moles = mass/ molar mass </em>

Number of moles =  43 g/ 97.5 g/mol

Number of moles = 0.44 mol

Number of moles of Oxygen:

<em>Number of moles = mass/ molar mass </em>

Number of moles =  44.2 g/ 32 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.

                             ZnS        :       ZnO

                                2          :          2

                              0.44       :         0.44

                              O₂          :          ZnO

                              3           :            2

                              1.4          :           2/3×1.4 =0.93

The number of moles of zinc oxide produced by ZnS are less so it will limiting reactant.

Mass of zinc oxide:

Mass = number of moles / molar mass

Mass = 0.44 mol / 81.38 g/mol

Mass = 0.00541 g

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A geological sample is found to have a Pb-206/U-238 mass ratio of 0.337/1.00. Assuming there was no Pb-206 present when the samp
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Answer:

2.1x10⁹ years

Explanation:

U-238 is a radioactive substance, which decays in radioactive particles. It means that this substance will lose mass, and will form another compound, the Pb-206.

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(mi-m)/m = 0.337/1

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Substituing mi in the expression of half-life:

m = 1.337m/2ⁿ

2ⁿ = 1.337m/m

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3 years ago
One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin c, c6h8o6). given that one cup
kodGreya [7K]
The question is incomplete. Complete question is read as:
'<span>One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin C, C6H8O6). Given that one cup = 218.0 mL calculate the molarity of vitamin C in organic juice.'
..........................................................................................................................
Answer:
Given: weight of solute (ascorbic acid) = 115 mg = 0.115 g
Volume of solution = 218.0 mL = 0.218 L
Molecular weight of ascorbic acid = 176.12 g/mol.

Now, Molarity = </span>\frac{\text{weight of solute(g)}}{\text{Molecular weight X Vol. of solution(l)}}
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Answer: Molarity of solution = </span>0.002995 mol/dm3<span>

</span>
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