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Soloha48 [4]
3 years ago
9

3b×+7c 2×2+4 3×3_6×+5 7y +8s_3

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

6

Step-by-step explanation:

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Slav-nsk [51]

Answer:

i think thats correct

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2 years ago
Expression <br> (27)x/3 equivalent
Ludmilka [50]

Answer:9x hope it helps

Step-by-step explanation:

8 0
3 years ago
-8)(56)=1<br><br> What is the missing value that makes the equation true?
Rudik [331]
the correct answer is -448
7 0
3 years ago
What is the equation of the line that passes through the point (-2,5) and has a<br> slope of -4?
adoni [48]

Answer:

\boxed {\boxed {\sf y= -4x -3}}

Step-by-step explanation:

We are asked to find the equation of a line given a point and the slope. We will use the point-slope formula.

y-y_1= m(x-x_1)

In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of this line is -4 and the line passes through (-2,5).

  • m= -4
  • x₁= -2
  • y₁ = 5

Substitute the values into the formula.

y-5 = -4 (x--2)

y-5 = -4 (x+2)

We are finding the equation of the line, so we should find the slope-intercept form or y=mx+b ( where m is the slope and b is the y-intercept).We must isolate the variable y on one side of the equation.

First, distribute the -4 on the right side of the equation. Multiply each term inside the parentheses by -4.

y-5=( -4 *x ) + (-4* 2 )

y-5 =(-4x)+ (-8)\\y-5= -4x -8

5 is being subtracted from y. The inverse operation of subtraction is addition, so we will add 5 to both sides of the equation.

y-5 =-4x -8 + 5

y= -4x -3

The equation of the line is y= -4x -3. The slope of the line is -4 and the y-intercept is -3.

6 0
3 years ago
Find sin(2x), cos(2x), and tan(2x) from the given information.<br> tan(x) = − 1/2 , cos(x) &gt; 0
vodomira [7]

Answer:

  • sin(2x) = -4/5
  • cos(2x) = 3/5
  • tan(2x) = -4/3

Step-by-step explanation:

It may be easiest to start with tan(2x).

  tan(2x) = 2tan(x)/(1 -tan(x)²)

  tan(2x) = 2(-1/2)/(1 -(-1/2)²) = -1/(3/4)

  tan(2x) = -4/3 . . . . . still a 4th-quadrant angle

__

Then cosine can be found from ...

  cos(2x) = 1/√(tan(2x)² +1) = 1/√((-4/3)²+1) = √(9/25)

  cos(2x) = 3/5

__

Sine can be found from these two:

  sin(2x) = cos(2x)tan(2x) = (3/5)(-4/3)

  sin(2x) = -4/5

5 0
3 years ago
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