Answer:
0.675 m/s
Step-by-step explanation:
Let height of shadow= y,CD=x
Height of man=2 m
Speed of man= 

Therefore, 


Differentiate w.r.t t



When the man is 4 m from the building
Then, we have x=12-4=8 m

Substitute the values in above equation then, we get


Substitute the values then we get

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.
Answer:
24
Step-by-step explanation:
Answer:
D. 116
Step-by-step explanation:

V = (1/3)π(4)²(6.9)
V = 36.8π
V ≈ 115.55
<em>Note: You will NEVER use slant height to calculate the area, only to calculate the normal height if unknown. In this problem, we did not use it at all so try not to get confused!</em>
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<h2>BRAINLIEST please if this helped!</h2>
2,862 bacteria
6,200/26 = x/12
For one hour, there are 238.461538. Multiply that by 12 and get 2861.53846. Round to the nearest whole number and your answer is 2,862 bacteria.
Answer:
x-coordinate = 0
Step-by-step explanation:
(-10,1) , (5,-5)
m = (y₂ - y₁)/(x₂ - x₁) = ( -5 - 1 ) / ( 5 - [-10] )
= -6 / ( 5 + 10)
= -6/15 = -2/5
y - y₁ = m (x - x₁)
y - 1 = (-2/5) ( x - [-10] )
y - 1 = (-2/5) ( x + 10 )
5 * (y -1) = -2 (x + 10)
5y - 5 = -2x -20
2x + 20 + 5y -5 = 0
2x + 5y + 15 = 0
Another point (a, -3) in on this line
2 * a + 5 * (-3) = -15
2a -15 = -15
2a = -15 +15
2a = 0
a = 0
x-coordinate = 0