1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vovikov84 [41]
3 years ago
6

What is the maximum height at which the solvent should condense (in the condenser) during reflux? What might happen if the solve

nt condenses higher than this?
Chemistry
2 answers:
tiny-mole [99]3 years ago
7 0
The answer to the first part of question is: During condensation in reflux condenser, the maximum height is halfway up to the condenser.
And the answer to second question is this that if solvent condenses higher than this maximum height, all of the solvent may run back into the reaction flask or may be the reaction will start earlier. if the solvent do not go up than the maximum height, the reaction does not happen to start earlier.
Alex3 years ago
5 0

During buildup in reflux condenser, the greatest tallness is most of the way up to the condenser. In the event that dissolvable gathers higher than this most extreme tallness, the majority of the dissolvable may keep running over into the response cup or might be the response will begin prior, And if the dissolvable don't go up than the greatest stature, the response does not occur to begin prior.  

Further Explanation:  

Reflux:  

Heartburn is otherwise called acid reflux, corrosive acid reflux, or pyrosis. It happens when a portion of the acidic stomach substance return up into the throat. Heartburn makes a consuming agony in the lower chest zone, frequently in the wake of eating.  

reason for a reflux device:  

Reflux is a procedure including the buildup of vapors and the arrival of this condensate to the framework from which it began. It is utilized in mechanical and research center refining processes. It is likewise utilized in science to supply vitality to responses over an extensive stretch of time.  

Reflux is utilized:

To keep the dissolvable from dissipating, a reflux condenser is utilized. This is a glass segment with a subsequent segment encompassing it through which cool water streams. As vapor from the bubbling dissolvable ascents into inside section of the reflux condenser, it is cooled by the coat of water outwardly and consolidates.

Subject: chemistry  

Level: college

Keywords: Reflux, reason for a reflux device, Reflux is utilized.

Related links:  

Learn more about evolution on

brainly.com/question/9096211

brainly.com/question/11169982

You might be interested in
Someone please help me
Leno4ka [110]

Answer:

<h3>MASS AND VOLUME</h3>

Explanation:

I HOPE IT HELPS :)

5 0
3 years ago
Please help !!!
stiv31 [10]

Answer:

2KClO3 》》2KCl +3O2

C+ O2》》CO2

number of C moles

Required O2 moles (According to the mole ratio )

Relevant to the first equation, find the moles the KClO3, which is used to produce that amount of O2 moles

Now you can find the mass of KClO3

I mentioned the useful steps which can guide you to get the answer.

Explanation:

5 0
3 years ago
Calculate the amount of solvent needed to prepare 50g of 10% solution of Tincture iodine. Name the solvent.
sergeinik [125]

Answer:

Calculate the amount of solvent needed to prepare 50g of 10% solution of tincture Iodine.

Name the solvent

Explanation:

sodium

Hope it is helpful.....

7 0
3 years ago
Calculate the amount of heat energy required to heat up 15.9 grams of ice from -4 °C to 14°C.
Aleks [24]
Hi how are you doing today Jasmine
8 0
3 years ago
When a 0.235-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.275-g sample
andrew-mc [135]

Answer : The heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

Explanation :

First we have to calculate the specific heat calorimeter.

Formula used :

Q=m\times c\times \Delta T

where,

Q = heat of combustion of benzoic acid = 26.38 kJ/g = 26380 J/g

m = mass of benzoic acid = 0.235 g

c = specific heat of calorimeter = ?

\Delta T = change in temperature = 1.643^oC

Now put all the given value in the above formula, we get:

26380J/g=0.235g\times c\times 1.643^oC

c=68323.38J/^oC

Thus, the specific heat of calorimeter is 68323.38J/^oC

Now we have to calculate the heat of combustion of caffeine.

Formula used :

Q=c\times \Delta T

where,

Q = heat of combustion of caffeine = ?

c = specific heat of calorimeter = 68323.38J/^oC

\Delta T = change in temperature = 1.584^oC

Now put all the given value in the above formula, we get:

Q=68323.38J/^oC\times 1.584^oC

Q=108224.23J=108.2kJ

Now we have to calculate the moles of caffeine.

\text{Moles of caffeine}=\frac{\text{Mass of caffeine}}{\text{Molar mass of caffeine}}

Mass of caffeine = 0.275 g

Molar mass of caffeine = 194.19 g/mole

\text{Moles of caffeine}=\frac{0.275g}{194.19g/mole}=0.00142mol

Now we have to calculate the heat of combustion per mole of caffeine at constant volume.

\text{Heat of combustion per mole of caffeine}=\frac{108.2kJ}{0.00142mol}=76197.18kJ/mole

Therefore, the heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

4 0
3 years ago
Other questions:
  • A doctor measures a patient's temperature at 38.4C. convert this temperature to degrees fahrenheit
    14·1 answer
  • How reactive is an atom of Sodium (na) and why?
    15·1 answer
  • 1. Convert 421 °C to Kelvin
    15·1 answer
  • Is water wet? If so explain if not also explain please!
    7·2 answers
  • Which of the following molecules can form hydrogen bonds like it
    5·1 answer
  • 10.0 grams of a gas occupies 12.5 liters at a pressure of 42.0 mm Hg. What is the volume when the pressure has increased to 75.0
    7·2 answers
  • The electrons in an insulator are tightly bound to their atoms.
    6·2 answers
  • Given the standard heats of reaction
    14·1 answer
  • Before bonding, the atom’s electrons spend most of their time ___________________ the nuclei of each atom.
    14·1 answer
  • What mass of zinc oxide would be produced by the thermal decomposition of 375 grams of zinc carbonate? znco3 -&gt; zno co2
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!