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vovikov84 [41]
3 years ago
6

What is the maximum height at which the solvent should condense (in the condenser) during reflux? What might happen if the solve

nt condenses higher than this?
Chemistry
2 answers:
tiny-mole [99]3 years ago
7 0
The answer to the first part of question is: During condensation in reflux condenser, the maximum height is halfway up to the condenser.
And the answer to second question is this that if solvent condenses higher than this maximum height, all of the solvent may run back into the reaction flask or may be the reaction will start earlier. if the solvent do not go up than the maximum height, the reaction does not happen to start earlier.
Alex3 years ago
5 0

During buildup in reflux condenser, the greatest tallness is most of the way up to the condenser. In the event that dissolvable gathers higher than this most extreme tallness, the majority of the dissolvable may keep running over into the response cup or might be the response will begin prior, And if the dissolvable don't go up than the greatest stature, the response does not occur to begin prior.  

Further Explanation:  

Reflux:  

Heartburn is otherwise called acid reflux, corrosive acid reflux, or pyrosis. It happens when a portion of the acidic stomach substance return up into the throat. Heartburn makes a consuming agony in the lower chest zone, frequently in the wake of eating.  

reason for a reflux device:  

Reflux is a procedure including the buildup of vapors and the arrival of this condensate to the framework from which it began. It is utilized in mechanical and research center refining processes. It is likewise utilized in science to supply vitality to responses over an extensive stretch of time.  

Reflux is utilized:

To keep the dissolvable from dissipating, a reflux condenser is utilized. This is a glass segment with a subsequent segment encompassing it through which cool water streams. As vapor from the bubbling dissolvable ascents into inside section of the reflux condenser, it is cooled by the coat of water outwardly and consolidates.

Subject: chemistry  

Level: college

Keywords: Reflux, reason for a reflux device, Reflux is utilized.

Related links:  

Learn more about evolution on

brainly.com/question/9096211

brainly.com/question/11169982

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A 5.00g piece of metal is heated to 100.0°C, then placed in a beaker containing 20.0 of water at 10.0°C. The temperature of the
Ahat [919]
Answer:

This metal has a specific heat of 0.9845J/ g °C

Explanation:
Step 1: Given data
q = m*ΔT *Cp
⇒with m = mass of the substance
⇒with ΔT = change in temp = final temperature T2 - initial temperature T1
⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = TO BE DETERMINED)

Step 2: Calculate specific heat
For this situation : we get for q = m*ΔT *Cp
q(lost, metal) = q(gained, water)

- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)
-5 * (15-100)(Cpmetal) = 20* (15-10) * (4.184J/g °C =
-5 * (-85)(Cpmetal) = 418.4

Cpmetal = 418.4 / (-5*-85) = 0.9845 J/g °C

This metal has a specific heat of 0.9845J/ g °C
7 0
3 years ago
Summarize how methylmercury can biomagnify in the food chain. <br><br>​
dmitriy555 [2]

Answer:

it can change the ways others eat

Explanation:

because the methylmercury depends on the animal

4 0
3 years ago
How many moles and numbers of ions of each type are present in the following aqueous solution? 63.1 mL of 1.85 M magnesium chlor
Alexxandr [17]

Answer:

We have 0.117 moles Mg^2+ and 0.234 moles Cl-

The number of Mg^2+ ions =  7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

Explanation:

Step 1: Data given

Volume of magnesium chloride = 63.1 mL

Concentration of solution = 1.85 M

Step 2: Calculate moles MgCl2

Moles MgCl2 = concentration * volume

Moles MgCl2 = 1.85 M * 0.0631 L

Moles MgCl2 = 0.117 moles

Step 3: Calculate moles of ions

MgCl2 → Mg^2+ + 2Cl-

For 1 mol MgCl2 we have 1 mol Mg^2+ and 2 moles Cl-

For 0.117 moles MgCl2 we have 0.117 moles Mg^2+ and 2*0.117 = 0.234 moles Cl-

The number of Mg^2+ ions = 0.117 * 6.022 *10^23 = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

4 0
4 years ago
Write the molecular formula for a compound with the possible elements c, h, n and o that exhibits a molecular ion at m+ = 91.043
timama [110]
We are given the mass spectrum data for this compound which has a molecular ion peak of m+ = 91.043 m/z. When we have an m+ peak that is an odd number, that suggests that there are an odd number of nitrogens, in this case we'll assume 1 nitrogen atom to start. Nitrogen has a mass of 14 so we will substract that from our initial value.

91- 14 (1N) = 77 m/z

We are also told that there are carbon, hydrogens and oxygens present, so we will assume there is at least one oxygen which has a mass of 16 and subtract that value.

77 - 16 (1 O) = 61 m/z

Now we will try to get as close as possible to the remaining mass with carbons that has a mass of 12, and fill the remaining mass with hydrogens that have a mass of 1.

61 / 12 = 5
5 x 12 = 60

61 - 60 (5 C) = 1 m/z and this leaves us with 1 H.

The current formula would be C₅HON, but this structure is impossible since we do not have enough hydrogens to satisfy the carbons. So we can try to use 4 carbons instead and fill the rest with hydrogens.

4 x 12 = 48
61 - 48 (4 C) = 13 m/z and this leaves us with 13 H.

The current formula would be C₄H₁₃ON. The most hydrogens we can have in a compound is 2n+2 where n is the number of carbons. So with 4 carbons the most hydrogens we could have is 10. Therefore, our formula has too many hydrogens and also cannot work. So we cannot make up the remaining mass with carbons and hydrogens, therefore, we should add another oxygen before working with carbons and hydrogens.

61 - 16 (1 O) = 45 m/z
45/ 12 = 3.75
3 x 12 = 36

45 - 36 (3 C) = 9 m/z which gives us 9 hydrogens left.

The current formula is now C₃H₉O₂N. To test if this formula works we can calculate the double bond equivalents (DBE), also known as degrees of unsaturation.
DBE = C - H/2 + N/2 + 1 = 3 - (9/2) + (1/2) + 1 = 0

A value of 0 DBE tells us that there are no double bonds in this molecule but that the formula is a possibility so:

C₃H₉O₂N = 91 m/z
8 0
3 years ago
Which of the following properties decrease down a column in the periodic table?
dsp73

Answer:

Effective nuclear charge and ionization energy decreased down in the column.

Explanation:

Along Group:

As we move from top to bottom in group the atomic size increases with increase of atomic number. The electron is added into the next shell hence the valance electrons farther away from the nucleus and hold of nucleus become weaker on the valance electrons. The addition of electrons also increase the shielding and protect the outer electrons from the hold of nucleus. Thus it becomes easier to remove the electron from an atom and less energy is required that's why ionization energy decreases from top to bottom and effective nuclear charge also decrease because of shielding effect.

Along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons and shielding remain constant due to addition of electron in same shell. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases.

3 0
4 years ago
Read 2 more answers
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