The domain of a function is where we have a value for x.
Since that's the case the domain of f(x) = {x e R / 1 ≤ x < 5}
We see that we have a value for x = 1 cuz we have a filled circle, but we don't have a value for x = 5, look at the unfilled circle
So, our x can vary between 1 and 5, but can't be 5.
Answer:
3
Step-by-step explanation:
6x+2y=12
2y=6x-12
y=6x/2- 12/2
y=3x-6
Answer:
q .no d
Step-by-step explanation:
64p^3+125
4p^3+ 5^3
(4p+ 5 ) ( 4p^2- 4p *5 + 5^2)
(4p+5) (16p- 20p+ 25)
