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GrogVix [38]
3 years ago
11

$1.50 what if you took of the sales tax rate of a helmet.if the sales rate was5%,how much would be the original price of the hel

met?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0

Then it would be 1.50 + 1.50 *5 /100 = 1.50 + 0.075 = 1.575

So, the original price would be $1.575

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Veronica tells another classmate that ΔHAT is congruent to ΔPAM because of the AAA Theorem. Is Veronica correct in what she tell
SCORPION-xisa [38]

Answer: Veronica is not correct

Explanation:

The AAA theorem, aka the AA theorem, only applies to similar triangles. We cannot use it to prove two triangles are congruent or not. We would need to know info about at least one pair of sides. So based on this diagram, we don't have enough information to know if triangle HAT is congruent to triangle PAM or not.

A similar example to this is to consider two equilateral triangles. Let's call them triangle A and triangle B. If equilateral triangle A has side lengths of 2, and has side lengths of 10, we can see that the triangles are not congruent. However, the triangles are similar because the corresponding angles equal one another. One triangle is a scaled copy of the other. This example is a counterexample as to why the AAA theorem is not a valid congruence theorem.

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2 years ago
6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP
adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

     = 036^{o}

Sum of angles in a triangle = 180^{o}

<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

    = 96^{o}

<S = 96^{o}

Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

⇒ y = \frac{12.63338}{0.99452}

       = 12.703

y = 12.70 km

\frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

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