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LuckyWell [14K]
2 years ago
8

4 The expression (2x² + 6x + 5)-(6x² + 3x + 5) is

Mathematics
1 answer:
Sergio [31]2 years ago
4 0

Answer:

1) 4x² + 3x

Step-by-step explanation:

Add/Combine like terms:

2x² - 6x² = -4x²

6x - (+3x) = 3x

5 - (+5) = 0

Simplify: -4x² + 3x

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I have been stuck on the problem for so long. please help me:
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Answer:

D-2

Step-by-step explanation:

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6 0
3 years ago
You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an
ASHA 777 [7]

Answer:

a

  Yes

b

 P(1 \& 5) = \frac{1}{36}

c

 P(5 \& 1) = \frac{1}{36}

d

 P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

Step-by-step explanation:

From the question we are told that

     Two fair dice, one green and one red were rolled

Generally the  outcomes on the dice independent because the outcome on the first dice is not affected by the second die

Generally the  probability of getting a 1  on a dice rolled is  P(1) =  \frac{1}{6}

the  probability of getting a 5 on a dice rolled is  P(5) =  \frac{1}{6}

Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as

         P(1 \& 5) = \frac{1}{6}  *\frac{1}{6}

         P(1 \& 5) = \frac{1}{36}

Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as

          P(5 \& 1) = \frac{1}{6}  *\frac{1}{6}

         P(5 \& 1) = \frac{1}{36}

Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as

          P(5 \& 1 | 1\& 5  ) = \frac{1}{36} + \frac{1}{36}

         P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

8 0
3 years ago
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