Your initial instinct would be to solve this problem with this solution. 34 x 57 = 1,938 petals.
However, the word estimate is present; therefore, we have to consider that we need to get the approximate number and not the exact number of petals.
There is a general rule regarding estimation or approximation. You have to round it to the nearest place you have based on. In this problem we round it off to the nearest tens place.
If the number is below 5, you round it down: 34 is rounded down to 30 petals.
If the number is above 5, you round it up: 57 is rounded up to 60 sunflowers.
Thus, your equation would be : 30 x 60 = 1,800 petals (best estimate)
This is what I get. Total will be 4187.56 with Interest 2187.56.
By using the formula:
To find amount :
A=p (1+r/n)^n×t
Where
P=2000,r=3%,n=1,t=25
So plug in and solve A=2000(1+0.03/1)^1×25
To find interest you use formula A=p+I
A=4187.56, p=2000,i= we need to find.
4187.56=2000+I
4187.56-2000=I
2187.56=i
Answer:
c
Step-by-step explanation:
Answer:
y = -5/9x + 4.1
(try doing this yourself first with different points to make sure this is the right answer, because im to lazy to check myself but ill try checking D:)
Step-by-step explanation:
first you have to find the slope . to do this use the equation y2 - y1/ x2 - x1
so write as -2 - 3/ -7 - 2 is equal to -5/-9
so now write y = -5/9x + b
we must now find the y-intercept so substitute one of the points given. lets substitute 2,3 it looks easier. So it will look like 3 = -5/9(2) + b
3 = -5/9(2) + b
3 = -10/9 + b
b = 3 + 10/9
b = 4.111111
um just round to the tenth place
Answer:
Step-by-step explanation:
Given:
Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).
So, the 'x' value is 3 and 'y' value id -4.
Using Pythagoras Theorem, we find the hypotenuse.
Hypotenuse = 
Now, using the sine ratio for the angle, we have
Therefore, the value of 
is 
.
The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,
