Write the equation of the line that passes througlī the points (-2, 6)
1 answer:
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Answer: (a) IV (b) positive (c) (d) C (e)
<u>Step-by-step explanation:</u>
a) -
=
, which is located in Quadrant IV <em>per the Unit Circle. </em>
b) sec is . Cos is the x-coordinate. The x-coordinate inQuadrant IV is positive.
c) the reference angle is the angle from to 2π =
d) since the angle is below the x-axis and the reference angle is, then the angle is equal to
)
e) sec = ⇒ sec
=
=
=
=
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Answer: (a) (b) (0, -1) (c) A (d) -1
<u>Step-by-step explanation:</u>
a) -
=
-
=
b) is on the Unit Circle at (0, -1)
c) sin = which equals
on the Unit Circle.
d) sin is the y-coordinate. sin = -1