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Aleonysh [2.5K]
3 years ago
5

Estimate 8.2 x 6.7 divided by 0.46

Mathematics
2 answers:
forsale [732]3 years ago
7 0
In mixed number form it is 119 10/23
As an improper fraction it is 2747/23
In decimal form its estimated as 119.4 (tenth place)
Molodets [167]3 years ago
6 0

Answer:

119.40 rounded as a tenth of 1

120.00 rounded as a normal decimal

119.4%

120% (rounded)

12/10 (Improper rounded)

11/10 with 9 remainder

x = 119.40

Step-by-step explanation:


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Arte-miy333 [17]
More then 2 thats the only answer I can give
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4 years ago
Read 2 more answers
Type the correct answer in the box. Spell the word correctly.
Wittaler [7]

Answer:

Scarce demand / inflation

The word "scarce" means low on supplies or anything else.

Inflation is the term used when a price increases in the market.

These two terms together would best describe the higher demand.

Hope this helps, have a great day! ♥

7 0
3 years ago
Find the slope and y-intercept of the graph of 4x-3=36
Oxana [17]

Answer: Slope is undefined or aka infinity, and there is no y-intercept

<u>Step-by-step explanation:</u>

Using Slope-Intercept Form to find the slope and the y-intercept.

First, lets change 4x-3=36 into y=mx+b. When you change it into this form you'll see that it can't go into intercept form because x=39/4 and is a vertical line so the slope is undefined or aka infinity, and there is no y-intercept.

Hope this helps! Have a nice day! ❤

- Cutiepatutie

6 0
4 years ago
Si: P(x+2) = 2(x+2)^3 + x^2 +4x +4<br> Calcular : P(-4)
Tom [10]

Answer:

Step-by-step explanation:

6 0
3 years ago
On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
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