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Archy [21]
3 years ago
15

Is 41/50 closer to 9/11 or 10/11? Verify your answer

Mathematics
1 answer:
professor190 [17]3 years ago
6 0
First,
41/50 = 41 divide by 50 = 0.82

9/11 = 9 divided by 11 = 0.81

10/11= 10 divided by 11= 0.90

Answer: 9/11 is closer.
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3 0
3 years ago
What pattern is represented by the polynomial ?
Ymorist [56]

Answer:

choice C. Perfect square trinomial is correct.

Step-by-step explanation:

We need to find the pattern which is represented by the polynomial 4x^2+12x+9.

To find that pattern, we need to factor 4x^2+12x+9

4x^2+12x+9

=4x^2+6x+6x+9

=2x(2x+3)+3(2x+3)

=(2x+3)(2x+3)

=(2x+3)^2

which is a perfect square.

Hence choice C. Perfect square trinomial is correct.

8 0
3 years ago
Gabriel purchases a rug priced at $475. With sales tax, the total comes out to $513. What is the sales tax percentage?
Degger [83]

Answer:

The tax is 8%

Step-by-step explanation:

Take the final price and subtract the original price

513-475 = 38

Divide by the original price

38/475 =.08

Change to percent form

8%

The tax is 8%

8 0
2 years ago
Read 2 more answers
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
Simplify (5x^3+7x-8)+(2x^3-5x^2-x+3)​
Anna [14]

Answer:

Step-by-step explanation:

8 0
3 years ago
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