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2 years ago

A car traveling 118 miles uses 4 gallons of gas. At this rate, how many miles can it travel using 13 gallons of gas

Mathematics

2 answers:

DanielleElmas [232]2 years ago

6 0

<h2>383.5 miles </h2>

Step-by-step explanation:

<h3>118 miles = 4 gallons </h3><h3>118 ÷ 4 miles = 1 gallon</h3><h3>29.5 miles = 1 gallon</h3>

<h3><em><u>so</u></em>, <em><u>therefore</u></em></h3><h3>( 29.5 × 13 )miles = 13 gallons</h3><h3>383.5 miles = 13 gallons</h3>

<h2>MARK ME BRAINLIST</h2><h3>FOLLOW ME</h3>

erastova [34]2 years ago

3 0

Answer:

12 miles per gallon

Step-by-step explanation:

I hope this helps

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poizon [28]

C). (3, 29) would be your answer.

Explanation?:

Rewrite the equation in vertex form.

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use the vertex form, y = a(x - h)^2 + k, to determine the values of a, h, and k.

a = -3

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Hope this helps!

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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2

Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

$y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\$

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t = e^−2(0) = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

$\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt} = -2te^{-2t} = -2(0)e^{-2(0)} = 0$