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Colt1911 [192]
3 years ago
9

The perimeter of a quarter circle is 7.14 miles. What is the quarter circle's area?

Mathematics
1 answer:
Kamila [148]3 years ago
8 0

Answer:

A= 4.06 mi2

Step-by-step explanation:

A=πr2

C=2πr

A=C2

4π=7.142

4·π≈4.05683mi²

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Looking for some furniture for her new apartment, Susan visits the local swap meet in search of something cheap. Knowing that mo
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Unlike credit card purchases, interest charged on cash advances is already incurred even if you pay before the due date. 

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6 0
3 years ago
In his freshman year, Mario earned a C in algebra, a B in English, an A in science, and a C- in geography. As a sophomore, he ea
Leya [2.2K]

from what I know

A=4

B=3

C=2

and a plus adds 0.33 and a minus minuses 0.33

question wants us to find yearly average or average per 1 year

since these grades span over 2 years, we must divide the total average by 2

averagefresh=sum of fresh grades/4 grades per year

averagesoph=sum of soph grades/4 grades per year

yearlyaverage=(averagefresh+averagesoph)/2


freshman:

(C)+(B)+(A)+(C-)=2+3+4+(2-0.33)=10.67


sophomore:

(B+)+(A-)+(C+)+(B-)=(3+0.33)+(4-0.33)+(2+0.33)+(3-0.33)=12


averagefresh=10.67/4=2.6675

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7 0
3 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
3 years ago
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