Answer:
k = 1.2
Step-by-step explanation:
Solving for t when the account value is 30,000, we have ...
30,000 = 25,000e^(0.0198t)
30,000/25,000 = 1.2 = e^(0.0198t)
ln(1.2) = 0.0198t
t = ln(1.2)/0.0198
Matching this with the form ...
t = ln(k)/0.0198
we see that k = 1.2.
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k is the multiplier of account value in time period t.
35 is the first answer (BAE ~ DAC)
36. We must divide 20 by 2 to get 10 because all the other sides are 2x the size. 3x-5=10 (Add 5) 3x=15 (Divide by 3) x=5 so the last answer choice is correct.
Answer:
-64/3 HOPE THIS HELPS if you need more help let me know
9514 1404 393
Answer:
1. ∠EDF = 104°
2. arc FG = 201°
3. ∠T = 60°
Step-by-step explanation:
There are a couple of angle relationships that are applicable to these problems.
- the angle where chords meet is half the sum of the measures of the intercepted arcs
- the angle where secants meet is half the difference of the measures of the intercepted arcs
The first of these applies to the first two problems.
1. ∠EDF = 1/2(arc EF + arc UG)
∠EDF = 1/2(147° +61°) = 1/2(208°)
∠EDF = 104°
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2. ∠FHG = 1/2(arc FG + arc ES)
128° = 1/2(arc FG +55°) . . . substitute given information
256° = arc FG +55° . . . . . . multiply by 2
201° = arc FG . . . . . . . . . subtract 55°
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3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.
∠T = 1/2(arc FS -arc US)
∠T = 1/2(170° -50°) = 1/2(120°)
∠T = 60°
