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Novay_Z [31]
3 years ago
5

(−1) to the power of 3

Mathematics
2 answers:
IceJOKER [234]3 years ago
6 0

Answer:

-1

Step-by-step explanation:

Note that whenever you have a odd number in the power sign, you keep the sign. If the power number is even, you flip the sign.

In this case:

(-1)³ = (-1)(-1)(-1)

(-1)(-1) = 1

(1)(-1) = -1

-1 is your answer

~

stiv31 [10]3 years ago
3 0

(-1) ^3

-(1) * (-1) * (-1)

1 * (-1)

=-1

Answer: -1

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Answer:

The domain is (-∞,∞)

Step-by-step explanation:

Since there's no limit to this function, the values are infinity.

6 0
2 years ago
A submarine starts at sea level and travels to a position that is a little lower than −24 feet. Use the drop-down menus to compl
Black_prince [1.1K]

Answer:

  1. The submarine's position means the distance it traveled is greater than 24 feet
  2. A possible position of the submarine is -27 feet

Step-by-step explanation:

Distance is generally a positive number. (Displacement, or position may be negative, as in this case.) If the sub started at 0 feet and went lower than -24 feet, it traveled a distance of more than 24 feet (greater than 24 ft).

Of the numbers listed, the only one lower than -24 is -27.

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3 years ago
The formula for finding the volume of a cone is V = 13πr2h. The volume of a cone is 300 cm3 and the height of the cone is 10 cm.
Kryger [21]
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4 0
2 years ago
Suppose the population of a town is 98,000 in 2014. The population increases at a rate of 3.7 percent every year. What will the
Setler [38]

Answer: 121871

Step-by-step explanation:

Current population = 98000

Rate of increase = 3.7% / year

Total time = 2020 - 2014 = 6 years

Population in 2020 = 98000 * (1+ (3.7/100))^6

= 98000 * (1.037)^6  =  98000 * 1.243576 = 121870.505

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3 0
3 years ago
What is the value of C in the matrix equation below?
lara [203]

Given:

The matrix equation is:

\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}

To find:

The value of matrix C.

Solution:

Let A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}. Then the given equation can be rewritten as

A-C=B

-C=B-A

C=-(B-A)

C=A-B

On substituting the values of the matrices, we get

C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}

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C=\begin{bmatrix}-4&2&-7\end{bmatrix}

Therefore, the correct option is C.

6 0
2 years ago
Read 2 more answers
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