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mestny [16]
2 years ago
10

Someone, please answer I´m in math and none of the classmates I know knows what to do. The value of a new car decreases by about

15% in the first year. How much will a car be worth after one year if its initial value was $1,000? $5,000? $5,020? x $$dollars?
and can you explain, please
Mathematics
1 answer:
Liula [17]2 years ago
7 0

Answer:

1000=850 5000=4250  5020=4276

Step-by-step explanation:

Multiply 1000, 5000, and 5020 by .15 to get 15 percent of what is taken away each year.

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bezimeni [28]

Answer:

5.0/5

Step-by-step explanation:

4 0
3 years ago
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sertanlavr [38]

Answer: The system consists of parallel lines

Step-by-step explanation:

Given system of lines :

y=\dfrac13x-4

3y-x=-7

Substitute y=\dfrac13x-4 in 3y-x=-7,  we get

3(\dfrac13x-4)-x=-7\\\\\Rightarrow\ x-12-x=-7\\\\\Rightarrow\ -12=-7 , which is not true.

That means , system has no solution.

i.e. they are representing parallel lines. [Parallel lines do not intersect and hence they do not have solution.]

6 0
2 years ago
Consider the function f(x) = x2 + 2x – 15. What are the x-intercepts of the function?
Gnom [1K]

Answer:

Left-most x-intercept: (-5,0)

Right-most x-intercept: (3,0)

Step-by-step explanation:

X-intercepts are also known as roots, when y = 0.

In this function, y = 0 when x = -5 and x = 3.

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3 years ago
How do you solve the system:<br> y+1=2x<br> 5y+5=10x
Marta_Voda [28]

Answer:

choose "infinitely more solutions"

Step-by-step explanation:

Let's solve this system by substitution method

y+1=2x

- 1 = - 1

y = 2x -1   <-- sbstitute this in the next equation

---------------------------------------------------------------------------------

    5y+5 = 10x

5(2x -1) + 5 = 10x

10x -5 + 5 = 10x

10x + 0= 10x

- 10x = -10x

0 = 0      <-- infinitely more solutions

4 0
2 years ago
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Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

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g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

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This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
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