In the number 65.784, what place is the 7 in?

Helga [31]

Answer:

$\dfrac{1}{12}$

Step-by-step explanation:

Rewrite the denominators as products of factors, then cancel the common factors.

$\begin{aligned}\dfrac{5}{14} \times \dfrac{7}{30} & =\dfrac{5}{2 \cdot 7} \times \dfrac{7}{6 \cdot5}\\\\ & = \dfrac{5 \cdot 7}{2 \cdot 7 \cdot 6 \cdot 5}\\\\ & = \dfrac{1}{2 \cdot 6}\\\\ & = \dfrac{1}{12}{\end{aligned}$

5 0

2 years ago

Read 2 more answers

The population of rabbits on an island is growing exponentially. In the year 1990, the population of rabbits was 1200, and by 19

kobusy [5.1K]

Answer:

2023 rabbits

Step-by-step explanation:

The exponential model consists of the following expression:

$y = A \cdot r^{t}$

Where:

$A$ - Initial population.

$r$ - Increase rate.

$t$ - Time

$y$ - Current population.

The initial population and increase rate are, respectively:

$1200 = A \cdot r^{0}$

$A = 1200$

$1700 = 1200 \cdot r^{4}$

$r^{4} = \frac{1700}{1200}$

$r^{4} = \frac{17}{12}$

$r = \sqrt[4]{\frac{17}{12} }$

$r \approx 1.091$

The exponential model that predicts the population of rabbits is:

$y = 1200\cdot 1.091^{t}$

Lastly, the expected population for the year 1996 is:

$y = 1200\cdot 1.091^{6}$

$y\approx 2023.624\,rabbits$

5 0

4 years ago

4th grade math help & explain please

ohaa [14]

Nothing on the rectangle is shaded, unless the camera quality is poor.

0/12

7 0

3 years ago

A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra

VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that $N = 6$

4 blue, which means that $k = 4$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4$

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that $N = 6$

2 yellow, which means that $k = 2$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667$

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that $P(A) = 0.4 + 0.0667 = 0.4667$

Probability of both being the same color and blue:

40% probability that both are blue, which means that $P(A \cap B) = 0.4$

Desired probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571$

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0

3 years ago

Q.2. Separate the digits of the number "893451" as per National and

LuckyWell [14K]

Answer:

imm a bit sorry I could only answer the international one as the national is equal to international place value system

Step-by-step explanation:

eight hundred ninety three thousand four hundred fifty one

hth tth th h t o

8 9 3 4 5 1

I hope you understand

8 0

3 years ago