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LekaFEV [45]
3 years ago
7

I'm not sure how to answer this,​

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

Addition

Step-by-step explanation:

if you just add 32 to both sides you'll get h=3+g

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The question is in the photo
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A survey is targeted at 12-year-old children. Which questions are appropriate for the population? Select two options.
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If the sum of N25,300 is shared among three students P, Q, R such
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Answer:

Step-by-step explanation:

We begin with the fact that P + Q + R = 25300. Now we need to state all of those variables in terms of just one, since we can't have more than one unknown in an equation.

If Q is half as much as P, then

Q = 1/2 P

If R has twice as much as Q, then

R = 2Q, but since Q = 1/2P then

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7 0
3 years ago
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee
blagie [28]

Question

Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?

a)39x+30<45x+18

b) 45x+18>39x+30

c) 45x+18<39x+30

d)39x+18<45x+30

Answer:

c) 45x+18<39x+30

Step-by-step explanation:

Step 1

We have to find the Algebraic expressions for the cable companies

Cable company A charges $45 a month for cable plus a $18 installation fee.

Let the number of months be represented as x

Hence, this is represented as:

$45 × x + $18

= 45x + 18

Cable B charges $39 a month for cable plus a $30 fee for installation.

Let the number of months be represented as x

Hence, this is represented as:

$39 × x + $30

= 39x + 30

The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?

= Cable company A < Cable company B

= 45x + 18 < 39x + 30

Therefore option c is correct

8 0
3 years ago
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