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blagie [28]
2 years ago
10

Need help with stats!

Mathematics
1 answer:
Brut [27]2 years ago
8 0

Answer:

a) 1,440 ways

b) 59,280 or 64,000

Step-by-step explanation:

a) Aircraft boarding.

8 people, 2 in first class, boarding first, then 8 economy class.

The 2 people in first class board first, but they can board as AB or BA... so 2 ways here.

For the 6 economy class passengers, we have a permutation of 6 out of 6, so 720, as follows:

P(6,6) = \frac{6!}{(6 - 6)!} = 6! = 720

Since the two are independent, we multiply them to have a global number of ways: 2 * 720 = 1,440 different ways for the 8 passengers to board that plane.

b) combination lock.

Here we do have a little problem... the question doesn't specify if the 3 numbers are different numbers of not.  So, we'll calculate both:

Numbers go from 1 to 40 inclusively... so 40 possibilities.

Normally, in a combination lock, the numbers are different, so let's start with that one:

First number: 40 options available

Second number: 39 options available (cannot take the first one again)

Third number: 38 different options (can't take First or Second number again)

Overall, we then have 40 * 39 * 38 = 59,280 different lock combinations.

If we can pick pick the same number twice:

First number: 40 options available

Second number: 40 options available

Third number: 40 options available

Overall 40 * 40 * 40 = 64,000 different lock combinations

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andrew11 [14]

Answer:

(4, 5)

Step-by-step explanation:

Calculate the midpoint using the midpoint formula

midpoint = [( + ), ( + ) ]

with (,  ) = (1, 2) and (,  ) = (7, 8)

midpoint = [(1 + 7), (2 + 8) ]

              = (4, 5)

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Answer:

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Step-by-step explanation:

5(3) = 3(5)

or

x(y) = y(x)

I found this

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Read 2 more answers
Help ????????????????????
IgorLugansk [536]
The perimeter of a triangle is when u add all of the sides together
(8x - 7w) + (2x + 6y) + (3y + 5w) = 
10x + 9y - 2w is ur perimeter

8w + 12x - 9y
8w + 12x - 9y
8w + 12x + 5y
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the 1st, 2nd, and 4th answer choices are the same....so 3 of them are equal
7 0
3 years ago
Need help now!! 20 points!!
Gelneren [198K]

When you have something like this, all you need to do is substitute the values, the last is for what value of x

For the first one;

((x^2+1)+(x-2))(2)

(x^2+x-1)(2)

(2)^2+(2)-1

4+2-1

5

For the second one;

((x^2+1)-(x-2))(3)

(x^2-x+3)(3)

(3)^2-(3)+3

9-3+3

9

For the last one;

3(x^2+1)(7)+2(x-2)(3)

3((7)^2+7)+2((3)-2)

3(49+7)+2(3-2)

3(56)+2(1)

168+2

170

3 0
2 years ago
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