x = 2
<em>right</em><em> </em><em>option</em><em> </em><em>is</em><em> </em>(E).
Step-by-step explanation:
f(x) = x³ - 3x² + 12 in interval [-2, 4]
{taking f'(x) by doing derivative of f(x)}
f'(x) = 3x² - 6x
.•. f'(x) = 0
0 = 3x² - 6x
0 = 3x(x - 2)
0 = x - 2
x = 2
Answer:
(1, 3)
Step-by-step explanation:
Given coordinates of 2 endpoints, G(-2, 5) and H(4, 1), midpoint of AB is calculated as shown below:
Midpoint (M) of GH, for G(-2, 5) and H(4, 1) is given as:
Let 
Thus:
Coordinates of the midpoint of GH = (1, 3).
This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π
Answer:
A= 16
B=?
Step-by-step explanation: srry about the second one im also confused but i tried my best.
that will be not so shore of what will you think but if you used a thermometer and you see how it will change
