1/10=x hope that helps a bunch
9514 1404 393
Answer:
9n^4
Step-by-step explanation:
The divisor and quotient can be interchanged to find the divisor:
Such division is carried out by first finding the quotient of the highest-degree terms:
This value is used to multiply the denominator and subtract that product from the numerator to find the new numerator. The new numerator is zero, so the value that goes in Blank 1 is ...
9n^4
_____
The attachment shows the long division.
Your answer to the length on JL is 22
<span>Yes, she is reasoning correct, because:
6 1/4 and 2 3/4 are mixed fractions and you can substract them as it shown below:
1. You must substract the fractional parts (</span>which are: 1/4 and 3/4) of the mixed fractions. You can notice that the have the same denominator "4", so you only need write this denominaro and substract the numerators:
= (1-3)/4=-2/4
When you simplify the result, you obtain:
=-1/2
Now, you must sum the integer parts:
6-2=4
Finally, you obtain:
4 -1/2
The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
In the question ,
it is given that
the time taken to vacate the stadium = 20 minutes
number of exits = 25 exits
capacity of the stadium = 25000 spectators .
given that ,
time taken to exit the stadium varies directly with number of spectators and inversely with the number of exits .
time taken ∝ number of spectators ∝ 1/number of exits .
to remove the proportionality sign , we write the constant
time taken = k * (number of spectators)/(number of exits) .
20 = k * 25000/25
20 = k * 1000
k = 20/1000
k = 2/100
k = 1/50 = 0.02
So, to find the time taken for 21,000 spectators to vacate the stadium, if only 15 exits are functional , we use the formula
time taken = (0.02)*(21000/15)
= 0.02*1400
= 28
Therefore , The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
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