Lets x = width
length = x + 4 (4 meters longer than wide)
A = L * W
192 = x ( x +4)
192 = x^2 + 4x
x^2 + 4x - 192 = 0
(x +16)(x-12) = 0
x - 12 = 0, x = 12
x + 16 = 0, x = -16
so width x = 12
length = 12 + 4 = 16 (4 meters longer than wide)
answer. J
16
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
#SPJ1
Answer:
-7/2 = -2(x-1/2)^2
Step-by-step explanation:
0 = –2x^2 + 2x + 3
Subtract 3 from each side
-3 = –2x^2 + 2x
Factor out the -2
-3 =- 2(x^2 -x)
Take the coefficient of x and divide by 2 and square it
-1 /2 = -1/2 ^2 = 1/4
Add it to each side Remember the -2 on the outside so we need to multiply it by -2
-2 *1/4 = -1/2
-3 -1/2= -2(x^2 -x +1/4)
-7/2 = -2(x^2 -x +1/4)
-7/2 = -2(x-1/2)^2
