Answer:
The length of rectangle is 6 units and the width is 1.5 units
Step-by-step explanation:
Let
L -----> the length of rectangle
W ----> the width of rectangle
we know that
The area of rectangle is equal to
we have
so
-----> equation A
A rectangle width is one fourth it’s length
so
----> equation B
substitute equation B in equation A and solve for L
take square root both sides
Find the value of W
Answer:
Step-by-step explanation:
Since the 3 ft edge is on both sides of the pool, each dimension of the pool is 6 ft shorter than the corresponding dimension of the space. The pool will be 15 ft -6 ft = 9 ft in one direction and 20 ft -6 ft = 14 ft in the other direction.
The perimeter of the pool is the sum of its side lengths:
P = 9 ft + 14 ft + 9 ft + 14 ft = 2(9 ft +14 ft) = 2(23 ft)
P = 46 ft
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The area of the pool is the product of its length and width:
A = (14 ft)(9 ft) = 126 ft²
The perimeter and area are 46 ft and 126 ft², respectively.
Find using Pythagorean Theorem,
.
.
.
Hope this helps.
