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frez [133]
3 years ago
13

The volume of a cone is 3 X cubic units and its height is x units.

Mathematics
1 answer:
hram777 [196]3 years ago
4 0

The  complete questions says:

The volume of a cone is 3\pi x^3 cubic units and its height is x units.

Which expression represents the radius of the cone's base, in units?

Answer:

3x

Step-by-step explanation:

The volume of a cone is given by:

V=\frac{1}{3}\pi r^2 h

where

r is the radius of the base

h is the heigth of the cone

In this problem, we know:

The volume of the cone:

V=3\pi x^3 (1)

And its height:

h=x (2)

We can re-arrange the formula above to make r, the radius, the subject:

r=\sqrt{\frac{3V}{\pi h}}

And by substituting (1) and (2), we find the radius:

r=\sqrt{\frac{3(3\pi x^3)}{\pi x}}=\sqrt{9x^2}=3x

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PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

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