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KiRa [710]
3 years ago
5

What will happen to the absorption and/or emission spectral lines of an object moving away from Earth at high speed?

Physics
1 answer:
Rufina [12.5K]3 years ago
4 0

Answer:

c. They will be shifted toward the red end of the spectrum.

Explanation:

When the absorption or emission lines of a moving object away from from the earth at very high speed then the spectral lines  will be shifted toward the red end of the spectrum.This effect can be easily understand by Doppler effect..

So the our option c is correct.

c. They will be shifted toward the red end of the spectrum.

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A person lowers a bucket into a well by turning the hand crank, as the drawing illustrates. The crank handle moves with a consta
dimulka [17.4K]

Answer:

0.453 m/s

Explanation:

Assuming the handle has diameter of 0.4 m while inner part diameter is 0.1 m then the circumference of outer part is \pi d_h where d is diameter and subscript h denote handle. By substituting 0.4 for the handle's diameter then cirxumference of outer part is \pi\times 0.4\approx 1.256 m

The rate of rotation will then be 1.81/1.256=1.441 rev/s

Similarly, circumference of inner part will be \pi d_i where subscript i represent inner. Substituting 0.1 for inner diameter then

\pi\times 0.1\approx 0.3142 m

The rate of rotation found for outer handle applies for inner hence speed will be 0.3142*1.441=0.453 m/s

7 0
2 years ago
If someone looks far enough into space, they should be able to see the beginning of the universe true of false
kodGreya [7K]
The answer is no, it would be impossible to see the beginning of the universe
8 0
2 years ago
The acceleration due to gravity on the moon is about 1/6 of the acceleration due to gravity on the earth. A net force F acts hor
uysha [10]

Answer:

c.a_m

Explanation:

We are given that

Acceleration due to gravity on the moon=a_m

Acceleration due to gravity on the earth=a_e

g_m=\frac{1}{6}g_e

Net force due to am on an object on moon=F_{net}=ma_m

There is no friction and no drag force and there is no gravity involved

Then, the force acting on an object on earth=F=ma_e

F=F_{net}(given)

ma_m=ma_e

a_e=a_m

Hence, option c is true.

3 0
2 years ago
Calculate the change in length of concrete sidewalk (coefficient of linear expansion for concrete is 12*10^-6/celcius) that is 1
anyanavicka [17]

Answer:

The answer to your question is 5.4 cm

Explanation:

This problem refers to calculate the change in length in one dimension due to a change in temperature.

Data

α = 12 x 10⁻⁶

Lo = 150 meters

ΔT = 30 °C

Formula

                    ΔL/Lo = αΔT

solve for ΔL

                    ΔL = αLoΔT

Substitution

                    ΔL = (12 x 10⁻⁶)(150)(30)

Simplification

                    ΔL = 0054 m = 5.4 cm

7 0
3 years ago
An eagle carries a fish up 50 m into the sky using 90 N of force. How much work did the eagle do on the fish? (Work: W = Fd)
Leno4ka [110]
<span>Work: W = Fd. 50(distance) multiplied by 90(force) would equal 4500 J or, answer D</span>
4 0
3 years ago
Read 2 more answers
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