The Joule is a unit of energy, not Force
George's speed per second is 76.92 m/s
George's velocity in meters per second was 38.46 m/s (North)
<u>Explanation:</u>
When dividing the total distance covered by object by time, we get the value for average speed.

<u>Given:</u>
t = 13 seconds
Calculate the distance without consideration of motion’s direction. So, the distance walks 750 m north first, and then turn around walks 250 m south, so the total distance covered is
d = 750 + 250 = 1000 meters
To find the rate per second, simply divide the distance by the time.

In given case, the students walks 750 m north first, and then turn around walk 250 m south. The displacement is the distance in a straight line between the initial and final position: therefore, in this case, the displacement is
d = 750 (north) - 250 (south) = 500 m (north)
The time taken is t = 13 s
So, the average velocity is
(North)
And the direction is north (the same as the displacement).
Answer:
momentum of iron ball is greater than wooden ball
Explanation:
when metal ball (iron ball) and wooden drop are drop from same elevation and reaching the ground after same time. at this position the iron ball has greater momentum than wooden ball
we know that momentum is defined as
P=Mv
and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time and same distance it mean also velocity will be same for both ball. therefore from above relation we have
Miron*V > Mwood*V i.e.
momentum of iron ball is greater than wooden ball
Answer:
0.7 mJ
Explanation:
<u>Identify the unknown: </u>
The work required to turn the dial from 180° to 0°
<u>List the Knowns: </u>
Capacitance when the dial is set at 180°: C = 350 pF = 350 x 10^-12 F Capacitance when the dial is set at 0°: C = 100 pF = 100 x 10^-12 F
Voltage of the battery: V = 130 V
<u>Set Up the Problem:</u>
<em><u>Energy stored in a capacitor: </u></em>
U_c=1/2*V^2*C
=1/2*Q^2/C
<em><u>When the dial is set at 180°:</u></em><em> </em>
U_c=1/2*(130)^2*350*10^-12=10^-4
Q=√2*U_c*C=4*10^-7
<u><em>When the dial is set at 0°:</em></u>
U_c=1/2*(4*10^-7)^2/100*10^-12
=8*10^-4 J
<u><em>Solve the Problem: </em></u>
ΔU_c=7*10^-4 J
=0.7 mJ
note:
there maybe error in calculation but method is correct