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melomori [17]
3 years ago
6

If an object moves in uniform circular motion in a circle of radius R = 1.0 meter, and the object takes 4.0 seconds to complete

ten revolutions, calculate the magnitude of the velocity around the circle. (Note: Remember, 10 revolutions is a counting number and not a measurement.) v=_____ m/s 1.6 m/s 2.5 m/s 5 m/s 16 m/s
Physics
2 answers:
boyakko [2]3 years ago
7 0

Answer: 2.5 m/s

Explanation: The velocity in in uniform circular motion is given by:

v=w^2*r where w is angular frequency

w=2*Pi/T  where T is the period

Finally we can calculate v= (2*Pi)^2/T^2*R   where R=1 m

ch4aika [34]3 years ago
3 0

Answer:

16m/s

Explanation:

The velocity v is given by the following relationship;

v=\omega R.......... (1)

where \omega is the angular velocity and R is the radius of the circular path. Angular velocity is defined as the  number of revolutions made by a body in circular motion per unit time or the angle turned through per unit time. It is measured in radians per second.

Also, the following relationship holds for \omega;

\omega=\theta /t...............(2)

where \theta is the angle turned through and t is the time taken.

Given; t = 4s, number of revolutions n = 10.

The angle turned can be obtained from the number of revolutions  by recalling the following;

1 revolution=2\pi rad\\hence\\10revolutions=10*2\pi rad=20\pi rad

Hence; \theta=20\pi rad

Substituting \theta and t into equation (2), the obtain the angular velocity as follows;

\omega=20\pi/4\\\omega=5\pi rads^{-1

Finally we substitute into equation (1) to obtain the linear velocity v as required.

v=5\pi*1=5\pi m/s

Taking \pi =22/7;

v = 15.7m/s which is approximately 16m/s

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Answer:

496.7 K

Explanation:

The efficiency of a Carnot engine is given by the equation:

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T_H is the temperature of the hot reservoir

T_C is the temperature of the cold reservoir

For the engine in the problem, we know that

\eta = 0.400 is the efficiency

T_C = 298.0 K is the temperature of the cold reservoir

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\frac{T_C}{T_H}=1-\eta\\T_H = \frac{T_C}{1-\eta} =\frac{298.0}{1-0.400}=496.7 K

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A 44-turn rectangular coil with length ℓ = 17.0 cm and width w = 8.10 cm is in a region with its axis initially aligned to a hor
Mumz [18]

Answer:

The maximum induced emf in the rotating coil  = 29.66V

The induced emf in the rotating coil when (t = 1.00 s) = 26.66V

The maximum rate of change of the magnetic flux through the rotating coil = 0.674Wb/s

Explanation:

Lets state the parameters we are being given right from the question:

Number of rectangular coil, (N) = 44

Length of Coil, l =17cm in meters we have; (l) = 17 × 10⁻² m

Width of Coil, w =8.10cm in meters we have; (w) = 8.10 × 10⁻² m

Magnitude of Uniform Magnetic Field (B) = 767mT= 765 × 10⁻³ T

Angular Speed of Coil, (ω) = 64 rad/s

(a)

To calculate the induced emf in the rotating cell,we can use the formula:

emf = NBAωsin(ωt)

For maximum induced emf, the value of sin(ωt) will be 1

emf_max = NBAω ; if (A = l × w) , we have:

emf_max  = NB(l × w)ω

subsitituting the parameters into the above equation; we have:

emf_max  = 44 × 765 × 10⁻³ ( 17 × 10⁻² × 8.10 × 10⁻² ) × 64

= 29.66V

(b)

At t = 1s, the induced emf is calculated as:

emf = NBAωsin(ωt)

substituting the parameters into the equation, we have:

emf =   44 × 765 × 10⁻³ ( 17 × 10⁻² × 8.10 × 10⁻² ) × 64 × sin (64 × 1)

=26.66V

(c)

To calculate the maximum rate of change of the magnetic flux through the rotating coil; we need to reflect on the equation for the maximum induced emf in terms of magnetic flux.

i.e emf_max = N\frac{d∅}{dt}

since emf_max = 29.66 and N = 44; we have:

29.66 =  44\frac{d∅}{dt}

\frac{d∅}{dt} = \frac{29.66}{44}

= 0.674 Wb/s

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s2008m [1.1K]

Answer:

a) Directamente proporcional

Explanation:

El peso se puede definir como la fuerza que actúa sobre un cuerpo o un objeto como resultado de la gravedad.

Matemáticamente, el peso de un objeto viene dado por la fórmula;

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Donde;

m es la masa del objeto.

g es la aceleración debida a la gravedad.

De la expresión matemática, podemos deducir que el valor del peso de un objeto es directamente proporcional a la masa del objeto.

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