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3 years ago

Pancakes or waffles ?

Mathematics

2 answers:

GarryVolchara [31]3 years ago

7 0

The answer to this is waffles

Zarrin [17]3 years ago

5 0

Answer

waffles

Step-by-step explanation:

pancakes are gay

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Find the value of x y and z

poizon [28]

I think you can plus like 180 plus that or 180 minus butttt it’s bc the angle looks like a “C” so you plus

5 0

3 years ago

A bowl has 3 red beads and 7 blue beads. Two beads are selected at random one at a time. First a red bead is drawn and placed on

IceJOKER [234]

The probability that first a red bead is drawn and next a blue bead is drawn is 7/30,and both events are dependent

<h3>How to determine the probability?</h3>

The distribution of the beads are:

Red = 3

Blue = 7

Total = 10

The probability of selecting the red bead first is:

P(Red) = 3/10

When the red bead is selected, the number of beads becomes 9

So, the probability of selecting a blue bead is

P(Blue) = 7/9

The probability of the event is then calculated using:

P = 3/10 * 7/9

Evaluate

P = 7/30

Hence, the probability of the event is 7/30

Read more about probability at:

brainly.com/question/25638875

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7 0

2 years ago

X two the 2 power =144

Alina [70]

The answer to your question is 12

4 0

3 years ago

Read 2 more answers

) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection

RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

$C_{(m,n)} = \frac{m!}{n!(m-n)!}$

In this question, m = 18, n = 9. So the total number of possibilities is:

$T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620$

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

$D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715$