Answer:
b
Step-by-step explanation:
because 4 yellow is negative and 2 red is positive and that would be -4+2=-2 and that makes b your answer
The square root of 36 is 6
The square root of 25 is 5
It is in between 5 and 6
Option A: The minimum number of colors needed to color the graph is 2
Explanation:
Given that ABCDEF is a graph with 6 vertices.
We need to determine the minimum number of colors needed to color the graph with 6 vertices.
To determine the minimum number of colors for the graph, let us use the chromatic number.
The chromatic number is the minimum number of colors that is required to color the graph in such a way that no two adjacent vertices must have the same color.
According to the chromatic number, if the graph with even number of vertices, then its chromatic number is 2.
Since, ABCDEF is a graph with 6 vertices, then the minimum number of color needed to color the graph is 2.
Therefore, the minimum number of colors needed to color the graph is 2.
Hence, Option A is the correct answer.
The answer to your question is H I know this because I did the math on a sheet of paper
Answer:
x = 2.1
Step-by-step explanation:
Instantaneous rate of change of f = ![\frac{df(x)}{dx}](https://tex.z-dn.net/?f=%5Cfrac%7Bdf%28x%29%7D%7Bdx%7D)
![= \frac{d}{dx}(x^{3}+5x)\\ =3x^{2} + 5](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E%7B3%7D%2B5x%29%5C%5C%20%20%3D3x%5E%7B2%7D%20%2B%205)
Average rate of change of f in an interval [a,b] = ![\frac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=%5Cfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
Average rate of change = ![\frac{f(3)-f(1)}{3-1} = \frac{(3^{3} + 5(3)) - (1^{3} + 5(1))}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bf%283%29-f%281%29%7D%7B3-1%7D%20%3D%20%5Cfrac%7B%283%5E%7B3%7D%20%2B%205%283%29%29%20-%20%281%5E%7B3%7D%20%2B%205%281%29%29%7D%7B2%7D)
![=\frac{(27+15) - (1 + 5)}{2}=\frac{42-6}{2}\\ \\= \frac{36}{2} = 18](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%2827%2B15%29%20-%20%281%20%2B%205%29%7D%7B2%7D%3D%5Cfrac%7B42-6%7D%7B2%7D%5C%5C%20%20%5C%5C%3D%20%5Cfrac%7B36%7D%7B2%7D%20%3D%2018)
At the point when instantaneous rate of change = Average rate of change,
![3x^{2} + 5 = 18\\\\3x^{2} = 18-5 = 13](https://tex.z-dn.net/?f=3x%5E%7B2%7D%20%2B%205%20%3D%2018%5C%5C%5C%5C3x%5E%7B2%7D%20%3D%2018-5%20%3D%2013)
Divide both sides by 3
![\frac{3x^{2} }{3}=\frac{13}{3}\\ \\x^{2} = 4.3333](https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E%7B2%7D%20%7D%7B3%7D%3D%5Cfrac%7B13%7D%7B3%7D%5C%5C%20%20%5C%5Cx%5E%7B2%7D%20%3D%204.3333)
Take the square root of both sides
±![\sqrt{4.3333}](https://tex.z-dn.net/?f=%5Csqrt%7B4.3333%7D)
±2.0817
![x = 2.0817 or x = -2.0817](https://tex.z-dn.net/?f=x%20%3D%202.0817%20or%20x%20%3D%20-2.0817)
But since the value of x has to be between 1 and 3,
x = 2.0817 ≅ 2.1