A sandbox has a perimeter of 21 1/2 feet. If the length is 5 1/4 feet, what is the area of the sand box?

1 answer:

4 0

The perimeter of a rectangle is twice the sum of length and width, so the sum of length and width is half the perimeter, 10 3/4 ft.

The width will be the difference between this and the length, hence 5 1/2 ft.

The area is the product of length and width.
A = length×width
A = (5.25 ft)×(5.5 ft) = 28.875 ft²

The area of the sandbox is 28 7/8 ft².

You might be interested in

Quadratic functions whose zeros are -2 and -9

nika2105 [10]

Answer: f(x)= $x^{2} +11x+18$

Step-by-step explanation:

6 0

3 years ago

The equation x squared + y squared = r squared

WITCHER [35]

$(5-0)^2+(-2+0)^2=r^2\\
25+4=r^2\\
29=r^2\\\\
\boxed{x^2+y^2=\sqrt{29}}$

5 0

2 years ago

Two angles are complementary and the measure of one is 36

marysya [2.9K]

Answer:The angles are 63 degrees and 27 degrees
This is true because when you subtract 27 from 63 you get 36. And when you add 27 to 63 you get 90 aka the complimentary angle we’re looking for.

7 0

2 years ago

Two studies were done on the same set of data, where study I was a one-sided test and study II was a two-sided test. The p-value

mixer [17]

Answer:

$0.060$

Step-by-step explanation:

In a two tailed test the probability of occurrence is the total area under the critical range of values on both the sides of the curve (negative side and positive side)

Thus, the probability values for a two tailed test as compared to a one tailed test is given by the under given relation -

$p-value = P(Z< -\frac{\alpha }{2} )+P(Z >\frac{\alpha}{2})$ \

Here $P\frac{\alpha}{2} = 0.030$

Substituting the given value in above equation, we get -

probability values for a two tailed test

= $0.030 + 0.030\\= 0.060$

4 0

3 years ago

A farmer decides to enclose a rectangular garden, using the side of a barn as one side of the rectangle. What is the maximum are

kifflom [539]

Garden
max area is if the sides are as equal as possible
so he should try to make a square (ideal is a circle, but barn walls are normally straight)
squaer perimiter=4 times legnth of 1 side
perimiter=amount of fencing=80
80=4s
divide 4
20=s
one sides=20

area=legnth times width
in squaer, legnth=width

20=legnth
20=width
area=20 times 20=400

dimetions are 20ft by 20ft to give 400ft^2
(fun fact, if it were a circle, the area would be about 509.5ft^2)

answer is 20ft by 20ft and area=400ft^2

7 0

3 years ago