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3 years ago

Simplify the radical expression

Mathematics

1 answer:

melamori03 [73]3 years ago

8 0

Answer:

$x \: \sqrt[5]{ {y}^{5} }$

Step-by-step explanation:

$\sqrt[5]{ {x}^{5} {y}^{5} } \\ \\ = ({x}^{5} )^{ \frac{1}{5} } \sqrt[5]{ {y}^{5} } \\ \\ = {x}^{5 \times \frac{1}{5} } \times \sqrt[5]{ {y}^{5} } \\ \\ = x \: \sqrt[5]{ {y}^{5} }$

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What is the answer to this problem?

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i think the best answer for this question is A)

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3 years ago

Mary made 1/5 of a batch of cookies in 1/10th of an hour, how many batches of cookies can she make in one hour? This is unit rat

barxatty [35]

Answer:

1/5 ÷ 1/10 = 10/5

Step-by-step explanation:

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3 years ago

Find the missing value when given the modulus.

kolbaska11 [484]

Solving the complex number, we get the value of the missing value that is ‘a’ = -6

We have been given the expression as

|a – i| = √37 (1)

Which is an expression of complex number. The general expression of complex number is given as

z = x + iy

where x is the real part and iy is the imaginary part

To find the modulus value, the formula is given by,

|z| = |x + iy|

|z| = √[(real part)2 + (imaginary part)2]

|z| = √(x2 + y2)

According to the question, |z| = √37 (2)

Equating equation (1) and (2), we get

√(a2 + 1) = √37

(a2 + 1) = 37

a2 = 37 – 1

a2 = 36

a = √36

a = ±6

Now value of a can be 6 or -6. We have been given that the modulus is in third quadrant.

Hence the value will be negative. Therefore, the missing value will be -6.

Learn more about complex number here : brainly.com/question/5564133

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1 year ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

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2 years ago

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olasank [31]

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Step-by-step explanation:

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2 years ago