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N76 [4]
3 years ago
14

At the movies, you order 3 boxes of popcorn and a bottle of water. The cost of the bottle of water is $1.75. Your total cost is

$9.25. Write and solve an equation to find the cost of one box of popcorn.
Mathematics
2 answers:
anastassius [24]3 years ago
8 0
X=cost of one box of popcorn.
we can suggest this equation:

3x+1.75=9.25

3x=9.25-1.75
3x=7.5
x=7.5/3
x=2.5

Answer: the equation to find the cost of one box of popcorn is 3x+1.75=9.25, and the cost of one box of popcorn is $2.5. 
bearhunter [10]3 years ago
6 0
9.25-1.75= 7.5. So, 7.5/3= $2.5 for one bag of popcorn.

Hope that helps.
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Not sure what exactly you meant, so i solved for both possibilities...

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The original value of the car is $18,000 it depreciates by 15% every year what is the value of the car after three years
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4 0
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PLEASE HELP ASAP: Sals sandwich shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $
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Answer:

y intercept (0,490)

I would use (Graphing equation standard form) to identify x and y intercepts. I will Plot the y intercept (0,490) and the x intercept (735,0)

,It will Connect the two intercepts with a straight line

2x + 3y = 1,470

3y = -2x + 1470

y = (-2x + 1470 ) / 3

y = -2/3 * x + 1470/3

y = -2/3 * x + 490

slope is -2/3

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Step-by-step explanation:

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3 years ago
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Ket [755]

Answer:

Correlation coefficient ≈ 0.9445

This indicates that the weight of a student increases as the height of the student increases.

Step-by-step explanation:

The rest of the question is the following table

value of x (<u>height</u>) are        58, 59,   60,  62,  63,  64,   66,  68,  70

Value of y (<u>weight</u>) are:      122, 128, 126, 133, 145, 136, 144, 150, 151

=======================================================

To calculate the correlation coefficient we will use the following form:

r = \frac{n(\sum xy)- (\sum x)(\sum y)}{\sqrt{n\sum x^2 - (\sum x)^2} \sqrt{n\sum y^2-(\sum y)^2} }

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So, the correlation coefficient =

r = \frac{9\times 78617- 570\times 1236}{\sqrt{9\times 36234-(570)^2}\sqrt{9\times 170694-(1236)^2}}\\

∴ r =  0.9445

So, weight of a student increases as the height of the student increases.

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