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jeyben [28]
3 years ago
7

What is the measure of one exterior angle of a regular hexagon?a. 60b.72c. 90

Mathematics
1 answer:
Molodets [167]3 years ago
5 0
To find the exterior angle measure we would use the following formula: 
\frac{360~degrees }{number ~of ~sides}
A regular hexagon has 6 sides so we divide: 
360/6 which equals 60 
So our final answer would be A. 60 
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Given the relation {(8,2),(3,6),(7,5),(k,4)}, which value of k will result in the relation not being a function? 5 points O1) 1
marin [14]

Answer:

choice 3.)  if k = 3  because then you have 2 domain values  f(3) = 6 and f(3) = 4, but this is not a function.

Step-by-step explanation:

f(3) should equal f(3)  

but f(3) = 6  and then f(3) = 4,  is a no no

6 0
3 years ago
Help me plz? I have no clue how
a_sh-v [17]
Take 2 points
(3, 9) and (0, 3)
Slope = (Y2 -Y1) ÷ (X2 -X1)
<span>Slope = (3-9) / (0-3)
</span><span>Slope = -6 / -3
</span><span>Slope = 2

The equation will have the form    </span><span>y = mx + b</span>
We can rearrange this to   b = y -mx
Let's take one of the points (3, 9) and the slope (m) and enter it into the formula:
b = -9 -2*3
b= -3
Now we enter all that data into b = y -mx
and get
y = 2x -3


5 0
3 years ago
What is the awnser to 6 x 17?
Semmy [17]

the answer to 6×7 is equal to 102

7 0
3 years ago
Read 2 more answers
Suzie looked at the diagram at right and wrote 134% = 134/100. Is she correct? Why or why not?
____ [38]

Answer:

yes

Step-by-step explanation:

since the numerator is higher then the denominator plus the extra amount 100/100 +34

3 0
3 years ago
Read 2 more answers
If a polynomial f(x) is divided by (x+a) and leaves the reminder is a and b are constants then
Virty [35]

f(-a) is the remainder when f(x) is divided by (x+a). This can be obtained by remainder theorem for polynomials.

<h3>What is the required remainder?</h3>

Given that f(x) is divided by (x+a) and leaves a reminder

Using the remainder theorem for polynomials we get,

f(x) = (x+a)·g(x) + r, where g(x) is the quotient and r is the remainder.

Put x = -a, then

f(-a) = (-a+a)·g(-a) + r

f(-a) = (0)·g(x) + r

f(-a) = r

f(-a) is the remainder.

Hence f(-a) is the remainder when f(x) is divided by (x+a).

Learn more about remainder theorem here:

brainly.com/question/1550437

#SPJ4

6 0
2 years ago
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