Answer:
Distance around the pool = 162.8 feet
Area of the pool = 957 square feet
Step-by-step explanation:
Distance around the swimming pool = Perimeter of the pool
Perimeter of the pool which is a composite figure will be,
= Circumference of the semicircle + Sum of three sides of the pool
= πr + 2×(length of the pool) + width of the pool
= 3.14×(10) + 2×40 + 20
= 62.8 + 80 + 20
= 162.8 ft
Area of the pool = Area of the semicircle + Area of the rectangular pool
= ![\frac{1}{2}(\pi)(r)^{2}+(\text{length}\times \text{Width})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Cpi%29%28r%29%5E%7B2%7D%2B%28%5Ctext%7Blength%7D%5Ctimes%20%5Ctext%7BWidth%7D%29)
= ![\frac{1}{2}(3.14)(10)^2+(40\times 20)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%283.14%29%2810%29%5E2%2B%2840%5Ctimes%2020%29)
= 157 + 800
= 957 square feet
Since work = force * distance, the answer would 5*.5, which is 2.5 J
The answer is $300 because you have to multiply 25x12. 10x25=250 and 2x25=50. 250+50=300.