Answer:
B. 5
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
y' = -2e⁻ˣcos(x) -sin(x)2e⁻ˣ +e⁻ˣsin(x)-cos(x)e⁻ˣ = e⁻ˣ(-2cos(x)-2sin(x)+sin(x) -cos(x))
=e⁻ˣ(-3cos(x)-sin(x))
y'' = -e⁻ˣ(-3cos(x)-sin(x)) + (3sin(x)-cos(x))e⁻ˣ
y'' = e⁻ˣ[3cos(x)+sin(x) + 3sin(x)-cos(x)] = e⁻ˣ[2cos(x)+4sin(x)]
y''+2y'+2y = 0
e⁻ˣ[2cos(x)+4sin(x)] + 2[e⁻ˣ(-3cosx-sinx)] + 2[2e⁻ˣ cos(x)−e⁻ˣ sin(x)]
e⁻ˣ[2cos(x)+4sin(x)-6cos(x)-2sin(x)+4cos(x)-2sin(x)]
e⁻ˣ[-4cos(x)+2sin(x)+4cos(x)-2sin(x)]
e⁻ˣ[0cos(x)+0sin(x)] = 0
70 / 35 = 2
So the 70 pound dog weights double the weight of the 35 pound dog, so he will eat twice as much.
2 x 2.5 = 5 cups
Meaning he will eat 5 cups of dry dog food a day.
By the same logic a 140 pound dog would have to eat twice what a 70 pound dog eats, that is 10 cups of dry dog food a day, so 7 1/2 cups are not enough.
Challenge: per pound a dog eats more than a cat. Since you know a 140 pound dog eats 10 cups, you can dive 140 by 10, to find out that each cup feeds 14 pounds, so half a cup would be the amount of food to feed a 7 pound dog, meaning that a dog weighing 1 pound less than a 8 pound cat would need the same amount of food, so it eats more than a cat.
I believe it’s 2 because rise/run and 14/7 = 2
