Option (4.) is the answer angel TRS......
The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
I really hope that helps cause I went all out and best of wishes!!
Answer: 16g - 25h
4 (-6g - 10h) + 3h - 4 (- 3h - 10g)
-24g - 40h +3h +12h +40g
16g - 25h
Step-by-step explanation:
if this is wrong im sorry
the answer would be x=−0.870452,0.712370
