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valentina_108 [34]
3 years ago
7

What is the median of this set of data?

Mathematics
2 answers:
Vladimir [108]3 years ago
8 0

Answer:

The median would be 103.

WARRIOR [948]3 years ago
6 0

Answer:

102

Step-by-step explanation:

this is actually the correct one

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PLEASE HELP ME OUT I NEED IT !!
lisov135 [29]

Answer:

(1/2 ,3) or (0.5, 3) is the same

Step-by-step explanation:

The midpoint between (3,5) and (-2,1) would be:

Apply the formula:

x1+x2 / 2 , y1 + y2 / 2

= 3 + (-2) / 2, 5 + 1 /2

= 1/2, 6/2

= 1/2 ,3 or 0.5, 3 is the same

Hope this helped :3

4 0
3 years ago
Frederico's checking account balance is -$24, and Neela's checking account balance is -$384. How many times the balance of Frede
Vitek1552 [10]

-24y = -384, y would equal 16.

6 0
3 years ago
Read 2 more answers
Having trouble with add or subtracting the given polynomials
Bumek [7]

7.

(2b^2+7b^2+b)+(2b^2-4b-12)

(9b^2+b)+(2b^2-4b-12)

9b^2+b+2b^2-4b-12

11b^2+b-4b-12

11b^2-3b-12

8.

(7g^3+4g-1)+(2g^2-6g+2)

7g^3+4g-1+2g^2-6g+2

7g^3-2g-1+2g^2+2

7g^3-2g+1+2g^2

7g^3+2g^2-2g+1

Hope this helps!

3 0
3 years ago
Read 2 more answers
A shop needs to mail 77 checks to the bank if they put 4checks in each envelope how many checks will be in the final envelope
andreev551 [17]
You have to divide 77 by 4 and then the reminder will be 1 so only one check will be there in the final envelop.
7 0
3 years ago
Read 2 more answers
A sequence is constructed according to the following rule: its first term is 7, and each next term is one more than the sum of t
Iteru [2.4K]

Answer:

5

Step-by-step explanation:

According to the described rule, we have

a_1=7\\ \\a_1^2=7^2=49\Rightarrow a_2=4+9+1=14\\ \\a_2^2=14^2=196\Rightarrow a_3=1+9+6+1=17\\ \\a_3^2=17^2=289\Rightarrow a_4=2+8+9+1=20\\ \\a_4^2=20^2=400\Rightarrow a_5=4+0+0+1=5\\ \\a_5^2=5^2=25\Rightarrow a_6=2+5+1=8\\ \\a_6^2=8^2=64\Rightarrow a_7=6+4+1=11\\ \\a_7^2=11^2=121\Rightarrow a_8=1+2+1+1=5\\ \\\text{and so on...}

We can see the pattern

a_5=a_8=a_{11}=a_{14}=...=5\\ \\a_6=a_9=a_{12}=a_{15}=...=8\\ \\a_7=a_{10}=a_{13}=a_{16}=...=11

In other words, for all k\ge 2

a_{3k-1}=5\\ \\a_{3k}=8\\ \\a_{3k+1}=11

Now,

a_{2018}=a_{3\cdot 673-1}=5

7 0
3 years ago
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