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dexar [7]
4 years ago
10

What happens when an electron moves from a higher energy level to a lower one

Chemistry
1 answer:
hjlf4 years ago
4 0
When an electron moves from a higher to a lower energy level, energy is released (often as light).
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Karolina [17]

Answer:

????

Explanation:

3 0
3 years ago
Radiometric dating is the workhorse of absolute dating. If you had a sample with a radioactive component with a half-life of 500
PSYCHO15rus [73]
The amount left over after T years where P is initial amount is P( \frac{1}{2})^{ \frac{t}{5000} }
it halves each time so after t times of the 5000 years have elapsed, the amount is now (1/2)^t of the original amount

find how many half lives

10000/5000=2
(1/2)^2=1/4
1/4 of original amount after 10000 years

after 50000 years
50000/5000=10
(1/2)^10=1/1024
1/1024 of original amount after 50000 years


it dissapears when it attains an amount you deem is nigligible, so if you had 1 mol of subsutance, you might say it dissapears when it gets to 10^-23 or about 6.02 molecules



5 0
4 years ago
How many valence electrons does He have
horsena [70]

Answer:

2 valence electrons

3 0
3 years ago
An energy profile for the reaction A⇌B (left), and the change in concentration of B as a function of time (right), with and with
RoseWind [281]

Answer:

<em>What quantity dictates the speed of a reaction?</em> The activation energy

Explanation:

According to the collision theory, when molecules collide, they must overcome an energy barrier for the reaction to take place. This energy, known as activation energy, is represented by the difference in energy between the initial state and the transition state. The higher the activation energy, the slower the reaction. That's why catalysts reduce the activation energy to accelerate the reaction.

3 0
4 years ago
Carbon-14 has a half-life of 5,730 years. If scientists discover a mummified Cro-Magnon specimen, they will first want to determ
ryzh [129]

Answer:

the specimen has 11460 years old

Explanation:

if the live sample has as initial amount of Yo C14, the dead sample will have 0.25Yo of C14.

the rate of decay of radiactive matter over time is

  • Y(t) = Yo * e (( - t * Ln2 ) / T)

∴ Y(t) = 0.25Yo;  T = 5730

⇒ 0.25Yo = Yo * e (( - t * Ln2 ) / 5730 )

⇒ 0.25 = e (( - t * Ln2 ) / 5730 )

⇒ Ln(0.25) = ( -  t * Ln2 ) / 5730

⇒ - 7943.466 = - t * Ln2

⇒ 7943.466 / Ln2 = t

⇒ t = 11460 year

4 0
3 years ago
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